Question

我目前正在开发一个简单的网站，人们可以在其中列出帖子。大部分代码都基于Michael Hartl的教程。我希望用户能够单击单独显示列表的链接。目前，列表＆＃39;每个用户都在

下找到

http://localhost:3000/users/id

每个商家信息都有自己的ID 这是我的路线

Rails.application.routes.draw do
    resources :users
    resources :sessions, only: [:new, :create, :destroy]
    resources :listings


  root 'static_pages#home'


  match '/signup',  to: 'users#new',            via: 'get'
  match '/signin',   to: 'sessions#new',          via: 'get'
  match '/signout', to: 'sessions#destroy',     via:'delete'
  match '/help',      to: 'static_pages#help',    via: 'get'
  match '/contact',   to: 'static_pages#contact',  via: 'get'
  match '/about',     to: 'static_pages#about',   via: 'get' 
  match '/new',     to: 'listings#new',           via: 'get'

这是我的listing_controller.rb

class ListingsController < ApplicationController
    before_action :signed_in_user, only: [:create, :destroy, :edit]
    before_action :correct_user,   only: :destroy

def create
    @listing = current_user.listings.build(listing_params)
    if @listing.save
        flash[:success] = "Job Post created"
        redirect_to current_user
        else
            render 'listings/new'
        end
    end

    def edit
    end

    def show
        @listing = Listing.find(params[:id])

    end

    def new
        @listing = Listing.new
        @listings = Listing.paginate(page: params[:page])
    end

def destroy 
    @listing.destroy
    redirect_to current_user
end

private 

def listing_params
    params.require(:listing).permit(:description, :location, :title)
end

def correct_user
    @listing = current_user.listings.find_by(id: params[:id])
    redirect_to current_user if @listing.nil?
end

def current_listing
    @listings = listing.find(params[:id])
end

end

我还在列出文件夹文件夹下为每个列表创建了一个显示页面。节目页面本身有效。这是列表

的show.html.erb

<div class="show_listing">

    <div class="col-md-6">
    <div class="col-md-6">
        <h3><%= @listing.title %></h3>
        <h3><%= @listing.location %></h3>
        <p><%= @listing.description %></p><br>
        <div class="center">
        <%= link_to "Apply Now", '#', class: "btn btn-info", data: {no_turbolink: true} %>
    </div>
    </div>
</div>
</div>

<div class="show_link_position">
<% if current_user == @listing.user %>
<%= link_to 'Edit', '#', class: "btn btn-link" %> |
<% end %>
<%= link_to 'Back', current_user, class: "btn btn-link" %>
</div>

现在，我希望在用户页面（每个列表下方）上有一个链接，可以单独链接到每个帖子。

我正在寻找类似的东西 how to display a link to individual microposts? (ruby on rails 3)

谢谢如果您需要更多信息，请告诉我

Answer 1

要从列有@listings列表的网页创建链接，您可能会有类似的内容......

<ol class="listings">
  <% @listings.each do |listing| %>
    <div class="listing">
      <h2><%= listing.title</h2>
      <h3><%= listing.location</h3>
      <p><%= listing.description</p>
      <%= link_to "Show", listing, class: "btn btn-link" %>
    </div>
  <% end %>
</ol>

Answer 2

以下是我为使其工作而做的事情（借助以下stackoverflow帖子如何显示单个微博的链接？（ruby on rails 3））

路线rb。

match '/users/:id/:id', to 'listings#show', via: :get, as: :user_listing

用户查看文件

添加链接

<li><%= link_to "Show", user_listing_path(id: @user.id, id: listing.id) %></li>

更改了我的listing_controller文件

def show
            @user = User.find_by_id(params[:id])
            @listing = Listing.find_by_id(params[:id])

        end

如何显示个别列表？ Ruby on Rails

2 个答案: