Question

var str = "123456";

if (!(/^\s*\d{6,7}\s*$/.test(str)))
{
    console.log("no");
} else {

    console.log("yes!");
}

当str的长度为6,7或10时，如何将此正则表达式更改为console.log是仅？

Answer 1

如下所示更改正则表达式，以便允许带有可选前导和尾随空格的6或7或10位数字。

^\s*(?:\d{10}|\d{6,7})\s*$

DEMO

<强>代码：

> var str = "1234567890";
undefined
> if (!(/^\s*(?:\d{10}|\d{6,7})\s*$/.test(str)))
... {
...  console.log("no");
... } else {
...  console.log("yes!");
... }
yes!

<强>解释

^                        the beginning of the string
\s*                      whitespace (\n, \r, \t, \f, and " ") (0 or
                         more times)
(?:                      group, but do not capture:
  \d{10}                   digits (0-9) (10 times)
 |                        OR
  \d{6,7}                  digits (0-9) (between 6 and 7 times)
)                        end of grouping
\s*                      whitespace (\n, \r, \t, \f, and " ") (0 or
                         more times)
$                        before an optional \n, and the end of the
                         string

Answer 2

只需尝试 OR ing。

^\s*(\d{6,7}|\d{10})\s*$

DEMO

模式说明：

  ^                        the beginning of the string
  \s*                      whitespace (\n, \r, \t, \f, and " ") (0 or more times)
  (                        group and capture to \1:
    \d{6,7}                  digits (0-9) (between 6 and 7 times)
   |                        OR
    \d{10}                   digits (0-9) (10 times)
  )                        end of \1
  \s*                      whitespace (\n, \r, \t, \f, and " ") (0 or more times)
  $                        the end of the string

Learn more...

数字列表上的正则表达式测试

2 个答案: