Question

我有一个像这样的mysql表

+-----+---------+-----------+-----------------+-------+
| id  | item_id | item_type | field_name      | data  |
+-----+---------+-----------+-----------------+-------+
| 258 |      54 | page      | field_interests | 1     | 
| 257 |      54 | page      | field_interests | 0     | 
| 256 |      54 | page      | field_author    | value | 
+-----+---------+-----------+-----------------+-------+

而且，我需要像这样构建查询

SELECT * FROM `content_fields_data` WHERE 
(`field_name`='field_author' AND `data`  LIKE '%lu%')
AND
(`field_name`='field_interests' AND `data`='1')

但它返回0行。如果我改变它或

SELECT * FROM `content_fields_data` WHERE 
(`field_name`='field_author' AND `data`  LIKE '%lu%')
**OR**
(`field_name`='field_interests' AND `data`='1')    

I need to select all rows 
WHERE 
  field_name.field_author.data LIKE '%text%'
AND
  field_name.field_interests.data = '1'

我可以解释它就像一个简单的函数：

IF table.field_name = 'field_author' THAN USE LIKE operator
IF table.field_name = 'field_interests' THAN USE equal(=) operator

任何人都可以帮助我吗？

感谢。

Answer 1

我认为你必须使用OR而不是AND（否则很明显你没有行！一件事情不能等于两件事......）。所以

SELECT * FROM table WHERE
(`field_name`='field_author' AND `field_author.data` LIKE '%jo%')
 OR
(`field_name`='field_interests' AND `field_interests.data`='0')
 OR
(`field_name`='field_interests' AND `field_interests.data`='1')

MySql按列值选择。列的Separeta算子

1 个答案: