我尝试向RestFul服务(带有Rest Framework的django)发送Http帖子。 GET方法工作正常,但POST方法给我带来了问题。我认为这可能是凭据问题或字符串格式问题。这是Android REST客户端代码。
HttpPost request = new HttpPost(urlString);
String encoding = Base64
.encodeToString(new String("username":"password")
.getBytes(), Base64.DEFAULT);
request.setHeader("Authorization", "Basic " + encoding);
request.setHeader("Content-type", "application/json");
JSONObject obj = new JSONObject();
obj.put("username", "apple");
obj.put("pw", "apple");
obj.put("email", "apple@gmail.com");
obj.put("name", "apple");
System.out.println(obj.toString());
StringEntity entity = new StringEntity(obj.toString());
entity.setContentType("application/json");
request.setEntity(entity);
// Send request to WCF service
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);
// Get the status of web service
BufferedReader rd = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
// print status in log
String line = "";
while ((line = rd.readLine()) != null) {
Log.d("Status Line", "Webservice: " + line);
}
这是Android aplog:
I/System.out﹕ {"email":"apple@gmail.com","username":"apple","name":"apple","pw":"apple"}
D/Status Line﹕ Webservice: {"username": ["This field is required."], "email": ["This field is required."], "pw": ["This field is required."], "name": ["This field is required."]}
这里是来自Django服务器的日志:
[05/Aug/2014 15:09:39] "POST /split/api_post_user/ HTTP/1.1" 400 151
我也尝试过CURL,以下脚本运行正常。
curl -u username:password -X POST \
--data '{"username" : "apple" , "pw" : "12345", "email" : "abc@gmail.com", "name" : "John" }' \
-H "Content-Type:application/json" \
$URL
logcat的第二行是来自服务器的响应。 例如,如果我使用错误的用户/密码对。它会给我
[Webservice: {"detail": "Invalid username/password"}].
如果我省略了setHeader("授权")部分,它会给我
[Webservice: {"detail": "Authentication credentials were not provided."}]
答案 0 :(得分:1)
在“活动类”
中的代码下面尝试以下代码..placeclass PlaceOrder extends AsyncTask<Void, Void, Void> {
@Override
protected Void doInBackground(Void... params) {
// TODO Auto-generated method stub
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPst = new HttpPost(
"yout_url");
ArrayList<NameValuePair> parameters = new ArrayList<NameValuePair>(
2);
parameters.add(new BasicNameValuePair("username", "apple"));
parameters.add(new BasicNameValuePair("pw", "apple"));
parameters.add(new BasicNameValuePair("email",
"apple@gmail.com"));
parameters.add(new BasicNameValuePair("name", "apple"));
httpPst.setEntity(new UrlEncodedFormEntity(parameters));
HttpResponse httpRes = httpClient.execute(httpPst);
String str = convertStreamToString(
httpRes.getEntity().getContent()).toString();
Log.i("mlog", "outfromurl" + str);
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
}
public static String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (Exception e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
从您的 onCreate 方法
调用new PlaceOrder().execute();
答案 1 :(得分:0)
我通过更改解码密码来解决问题。
String encoding = Base64
.encodeToString(new String("username":"password")
.getBytes(), Base64.URL_SAFE|Base64.NO_WRAP);