Question

我有2张桌子

#something - id, name, url
#something_users - id, id_something, email, password

我的模特

class Something extends Eloquent
{

    protected $table = 'something';

    protected $fillable = ['name', 'email', 'password'];

    public $errors;


    public function User()
    {
        return $this->belongsTo('User', 'id', 'id_something');
    }
}

class User extends Eloquent implements UserInterface, RemindableInterface {

    use UserTrait, RemindableTrait;


    protected $table = 'something_users';

    protected $hidden = array('password', 'remember_token');

    public function Something()
    {
        return $this->belongsTo('Something');
    }

}

控制器

$input = Input::all();

// also some validation
$this->db->fill($input);

$this->db->password = Hash::make(Input::get('password'));

$this->db->push();

$this->db->save();

SQL

insert into `something` (`name`, `email`, `password`) values...

我需要在第一个表（某物）和电子邮件中输入名称，将密码插入第二个（something_users）

怎么做？我对此有所了解。

Answer 1

你的关系有点搞砸了，你可能想要改变它们。请注意hasMany()与belongsTo()的对比。如果something只能有一个user，您可能希望将功能从hasOne()更改为hasMany()，将功能名称更改为user()这种方式更有意义。

class Something extends Eloquent {

    protected $table = 'something';

    public function users()
    {
        return $this->hasMany('User', 'id_something');
    }
}

class User extends Eloquent implements UserInterface, RemindableInterface {

    use UserTrait, RemindableTrait;

    protected $table = 'something_users';

    protected $hidden = array('password', 'remember_token');

    public function something()
    {
        return $this->belongsTo('Something', 'id_something');
    }
}

然后要保存something和user并将它们关联起来，这很容易。

$something = new Something;
$something->name = Input::get('name');
$something->url = Input::get('url');
$something->save();

$user = new User;
$user->email = Input::get('email');
$user->password = Hash::make(Input::get('password'));

$something->users()->save($user);

我没有看到您的构造函数，因此我不知道$this->db引用了哪个模型，但您可能希望替换somethings或users，具体取决于你有什么。为了保持依赖注入，我建议将依赖项命名为实际内容。

class SomeController extends BaseController {

    public function __construct(User $user, Something $something)
    {
        $this->user = $user;
        $this->something = $something;
    }

    public function someFunction()
    {
        $this->something->name = Input::get('name');
        $this->something->url = Input::get('url');
        $this->something->save();

        $this->user->email = Input::get('email');
        $this->user->password = Hash::make(Input::get('password'));
        $this->something->users()->save($this->user);
    }
}

Answer 2

Laravel 6。

我想使用一个名为RegisterController的控制器向用户表和客户表添加数据。

<?php

 namespace App\Http\Controllers\Auth;

 use App\User;
 use App\Customer;
 use App\Http\Controllers\Controller;
 use App\Providers\RouteServiceProvider;
 use Illuminate\Foundation\Auth\RegistersUsers;
 use Illuminate\Support\Facades\Hash;
 use Illuminate\Support\Facades\Validator;

 class RegisterController extends Controller
 {
/*
|--------------------------------------------------------------------------
| Register Controller
|--------------------------------------------------------------------------
|
| This controller handles the registration of new users as well as their
| validation and creation. By default this controller uses a trait to
| provide this functionality without requiring any additional code.
|
*/

use RegistersUsers;

/**
 * Where to redirect users after registration.
 *
 * @var string
 */
protected $redirectTo = RouteServiceProvider::HOME;

/**
 * Create a new controller instance.
 *
 * @return void
 */
public function __construct()
{
    $this->middleware('guest');
}

/**
 * Get a validator for an incoming registration request.
 *
 * @param  array  $data
 * @return \Illuminate\Contracts\Validation\Validator
 */
protected function validator(array $data)
{
    return Validator::make($data, [
        'name' => ['required', 'string', 'max:255'],
        'email' => ['required', 'string', 'email', 'max:255', 'unique:users'],
        'password' => ['required', 'string', 'min:8', 'confirmed'],
    ]);
}

/**
 * Create a new user instance after a valid registration.
 *
 * @param  array  $data
 * @return \App\User
 */

//this part is my code
protected function create(array $data)
{
    $user = User::create([
        'name' => $data['name'],
        'email' => $data['email'],
        'password' => Hash::make($data['password']),
        'role' => '2',
    ]);

    $customer = Customer::create([
        'user_id' => $user['id'],
        'firstname' => $data['name'],
        'lastname' => $data['name'],
        'email' => $data['email'],
        'address' => '',
        'phone' => '',
        'gender' => '',
    ]);

    return $user;
     }
 }

enter image description here

此答案不是最佳答案，因为此答案只是快捷方式代码，因此我的代码没有错误。将来可能还会出现另一个错误。但我希望我的回答能解决您的问题

Answer 3

我有类似的问题。我有2个表并保存这些数据

用户表：

 id, name, username, password, role

成员表：

 member_id, member_ic, member_contact, addressType_id, address, postcode, state, user_id

我可以将这些数据分别添加到数据库中，但不知道如何将它们添加到一起，如示例所示......

除此之外，数据仅在角色= 3时保存我正在使用https://github.com/bestmomo/laravel5-example

中的示例框架

任何人都可以指导我，谢谢你。

laravel插入多个表

3 个答案: