Question

我有一个名单。

约翰，山姆，彼得，杰克

我想用上面的每一个作为过滤器查询相同的sql。每个查询都会给我一个唯一的员工ID，我想用它来删除其他一些记录。

select emp_id from employee where emp_name like '%john%';

让我们说第一个查询，我得到的id为1001.所以删除查询就像是跟随。

delete from account_details where emp_id = 1001;
delete from hr_details where emp_id = 1001;
delete from pay_role_details where emp_id = 1001;

我必须重复这个以获取员工名单。伪代码就像是跟随。

var emp_list = ['john', 'jack', 'kate', 'peter', 'sam',...]

for each :employee_name in emp_list
    select emp_id as :var_emp_id from employee where emp_name like '%:employee_name%'; 

    delete from account_details where emp_id = :var_emp_id;
    delete from hr_details where emp_id = :var_emp_id;
    delete from pay_role_details where emp_id = :var_emp_id;
end loop

我想要一个PL-SQL查询来执行此操作。请帮忙。谢谢。

我尝试的是以下内容。

set serveroutput on;
begin
loop x in ('john','jack', 'kate') loop as :name
  select emp_id as var_emp_id from employee where emp_name like '%:name%';
  // delete queries  
end loop;
end;

P.S。虽然根据问题，如查询可能会导致多条记录，但在实际场景中，它保证只有一条记录。为什么我使用的是在实际场景中，它是参考数字列表而不是名称。参考编号有一些其他的前文和后期文本，我的逗号分隔列表只有数字。

Answer 1

也许以下内容会有所帮助：

BEGIN
  FOR aName IN (SELECT 'john'  AS EMP_NAME FROM DUAL
                UNION ALL
                SELECT 'sam'   AS EMP_NAME FROM DUAL
                UNION ALL
                SELECT 'peter' AS EMP_NAME FROM DUAL
                UNION ALL
                SELECT 'jack'  AS EMP_NAME FROM DUAL)
  LOOP
    FOR emp IN (SELECT * FROM EMPLOYEE WHERE EMP_NAME LIKE '%' || aName.EMP_NAME || '%')
    LOOP
      DELETE FROM ACCOUNT_DETAILS a WHERE a.EMP_ID = emp.EMP_ID;
      DELETE FROM HR_DETAILS h WHERE h.EMP_ID = emp.EMP_ID;
      DELETE FROM PAY_ROLE_DETAILS p WHERE p.EMP_ID = emp.EMP_ID;

      DBMS_OUTPUT.PUT_LINE('Deleted data for employee with EMP_ID=' || emp.EMP_ID);
    END LOOP;  -- emp
  END LOOP; -- aName
END;

研究这个，直到你了解它的工作原理和原因。

分享并享受。

Answer 2

你真的需要一个光标吗？尽可能跳过光标以避免对大量数据的性能/内存使用不佳。

delete from account_details inner join employee on account_details.emp_id = employee.emp_id where WHERE CONTAINS(employee.emp_name, '"John" OR "Sam" OR "Max"', 1) >0;

delete from hr_details inner join employee on hr_details.emp_id = employee.emp_id where WHERE CONTAINS(employee.emp_name, '"John" OR "Sam" OR "Max"', 1) >0;

delete from pay_role_details inner join employee on pay_role_details.emp_id = employee.emp_id where WHERE CONTAINS(employee.emp_name, '"John" OR "Sam" OR "Max"', 1) >0;

Answer 3

使用PL / SQL游标选择要删除的所有ID，然后循环它并在每次传递时发出DELETE语句。

有关游标的详细信息，请访问：http://www.oracle.com/technetwork/issue-archive/2013/13-mar/o23plsql-1906474.html

对于动态SQL，请参见此处：http://docs.oracle.com/cd/E11882_01/appdev.112/e25519/dynamic.htm#LNPLS627

代码示例：

    PROCEDURE delete_stuff
    IS

    id AS NUMBER;

    CURSOR your_cursor IS
    SELECT emp_id FROM employee WHERE CONTAINS(employee.emp_name, '"John" OR "Sam" OR "Max"', 1) > 0;

    OPEN your_cursor;
        LOOP
        FETCH your_cursor INTO id;
        EXIT WHEN your_cursor%NOTFOUND;

        EXECUTE IMMEDIATE 'DELETE FROM account_details WHERE emp_id = :id' USING id;
        EXECUTE IMMEDIATE 'DELETE FROM hr_details WHERE emp_id = :id' USING id;
        EXECUTE IMMEDIATE 'DELETE FROM pay_role_details WHERE emp_id = :id' USING id;

    CLOSE your_cursor;
    END LOOP;

    EXCEPTION 
    WHEN OTHERS THEN NULL;


END delete_stuff;

PL SQL循环遍历id列表

3 个答案: