Question

我有一个函数来获取数据库中的记录，如下所示：

public function test_records_with_join($select, $from, $joins=array(), $where, $order_by = null, $limit=null, $offset=null, $or_where=null, $group_by = null, $protect = TRUE){
            if (!$protect) $this->db->_protect_identifiers=false;
            if (is_array($select)){
                foreach ($select as $select){
                    $this->db->select($select, false);
                }
            }else{
                $this->db->select($select, false);    
            }

            $this->db->from($from);
            if (is_array($joins) && count($joins)>0){
                foreach ($joins as $join){
                    $this->db->join($join[0],$join[1],$join[2]);
                }
            }
            foreach ($where as $key => $value) {
                if ($key=='OR_WHERE') {
                    foreach ($value as $or_where_condition){
                        $this->db->where($or_where_condition);
                    }
                }
                else $this->db->where($key, $value, false);
            }

            if (!is_null($order_by)) $this->db->order_by($order_by);
            if (!is_null($group_by)) $this->db->group_by($group_by);

            if (!is_null($limit) && !is_null($offset)) $this->db->limit($limit, $offset);
            $result = $this->db->get();
            **Debug::dump($result);**
            if (isset($data)) unset($data);
            $data = array();
            foreach ($result->result() as $row){
                $data[] = $row;
            }
            echo count($data);
            return $data;
        }

查询1：

$query1 = $this->_product_model->test_records_with_join('GROUP_CONCAT(pr.id) as promo_ids, pr.updated_date, p.*, b.title as brand_title',
                                'products as p',
                                array(
                                    array('product_brands as b','b.id=p.brand_id','left'),
                                    array('promos as pr','FIND_IN_SET(p.id, pr.product_ids)','left')
                                    ),
                                $where, $order_by, null, null, null, 'p.id', FALSE);



$query2 = $this->_product_model->test_records_with_join('GROUP_CONCAT(pr.id) as promo_ids, pr.updated_date, p.*, b.title as brand_title',
                                    'products as p',
                                    array(
                                        array('product_brands as b','b.id=p.brand_id','left'),
                                        array('promos as pr','FIND_IN_SET(p.id, pr.product_ids)','left')
                                        ),
                                    $where, $order_by, 40, 0, null, 'p.id', FALSE);

这是最后执行的查询：

SELECT GROUP_CONCAT(pr.id) as promo_ids, pr.updated_date, p.*, b.title as brand_title
FROM products as p
LEFT JOIN product_brands as b ON b.id=p.brand_id
LEFT JOIN promos as pr ON FIND_IN_SET(p.id, pr.product_ids)
WHERE p.visible = 1
AND p.price>=0
AND p.price<=2500000
GROUP BY p.id
ORDER BY p.price DESC
LIMIT 40

更新

执行这些查询给了我这个：

object(CI_DB_mysql_result)#150 (8) {
  ["conn_id"] => resource(40) of type (mysql link)
  ["result_id"] => resource(189) of type (mysql result)
  ["result_array"] => array(0) {
  }
  ["result_object"] => array(0) {
  }
  ["custom_result_object"] => array(0) {
  }
  ["current_row"] => int(0)
  ["num_rows"] => int(720)
  ["row_data"] => NULL
}

int(720)

object(CI_DB_mysql_result)#1596 (8) {
  ["conn_id"] => resource(40) of type (mysql link)
  ["result_id"] => resource(191) of type (mysql result)
  ["result_array"] => array(0) {
  }
  ["result_object"] => array(0) {
  }
  ["custom_result_object"] => array(0) {
  }
  ["current_row"] => int(0)
  ["num_rows"] => int(40)
  ["row_data"] => NULL
}

使用第二个查询（$ per_page = 40，$ offset = 0），$ data中没有任何内容（计算它什么都不返回）。为什么？在重新初始化之前，我试图取消设置$ data，但没有发生任何事情。

我哪里做错了？提前谢谢！

CodeIgniter：活动记录查询的结果不同？

0 个答案: