var pic3 = document.createElement("IMG");
pic3.setAttribute("src", "img/mutantpre.jpg");
pic3.setAttribute("onclick", "display()");
pic3.setAttribute("id", "mutantpre");
pic3.setAttribute("height", "250px");
pic3.setAttribute("width", "150px");
document.getElementById("product4").appendChild(pic3);
我试图创建一个函数,在单击此图片时将所有图片设置为隐藏。但是从那个函数我不知道哪个被点击了。我如何弄清楚他们点击了哪一个获得了它的ID,以便我可以设置其他人的可见性。
答案 0 :(得分:0)
var pic3 = document.createElement("IMG");
pic3.setAttribute("src", "img/mutantpre.jpg");
pic3.setAttribute("onclick", "display('mutantpre')");
pic3.setAttribute("id", "mutantpre");
pic3.setAttribute("height", "250px");
pic3.setAttribute("width", "150px");
document.getElementById("product4").appendChild(pic3);
通过在点击功能中传递相同的id,你可以做到这一点
答案 1 :(得分:0)
您也可以这样做
var pic3 = document.createElement("IMG");
pic3.setAttribute("src", "#");
pic3.setAttribute("onclick", "display()");
pic3.setAttribute("id", "mutantpre");
pic3.setAttribute("height", "250px");
pic3.setAttribute("width", "150px");
document.getElementById("product4").appendChild(pic3);
function display(){
el = document.getElementsByTagName("img");
for(var i =0;i<el.length;i++){
el[i].addEventListener("click",function(e){
alert("the clicked one's id is "+e.target.id);
});
}
}
<强> Check the working Fiddle 强>
答案 2 :(得分:0)
显示功能:
function display(element){
var list = document.getElementsByTagName("img");
for(var i=0; i<list.length ; i++){
list[i].style.opacity = "0";
}
element.style.opacity="1";
}
在您的代码中,您必须拥有:
pic3.setAttribute("onclick", "display(this)");
答案 3 :(得分:0)
希望这有帮助!
var images = document.getElementsByTagName('img');
var activeImage = images[0]; // Assuming the first image is active at first
for(var i = 0; i < images.length; i++) {
var image = images[i];
image.onclick = function() {
activeImage.classList.remove("active");
this.classList.add("active");
activeImage = this;
}
}