Question

是否可以在词典中存储闭包（我们如何在词典中存储ObjC块）？例如：

   data = [String:AnyObject]()
   data!["so:c0.onSelection"] = {() in
       Debug.log(.Debug, message: "Hello, World!")
   }

Answer 1

你可以，但有一些限制。首先，函数类型不从AnyObject继承，也不共享公共基类。您可以拥有字典[String: () -> Void]和[String: (String) -> Int]，但不能将它们存储在同一个字典中。

我还必须使用一个typealias来定义字典，以便swift能够正确解析。以下是基于您的代码段的示例。

typealias myClosure = () -> Void
var data: [String: myClosure]? = [String: myClosure]()
data!["so:c0.onSelection"] = {() -> Void in
    Debug.log(.Debug, message: "Hello, World!")
}

Answer 2

我有不同的方法

我创建了一个＆＃34;持有者＆＃34;类可以保持你的闭包：

typealias SocialDownloadImageClosure = (image : UIImage?, error: NSError?) -> ()
typealias SocialDownloadInformationClosure = (userInfo : NSDictionary?, error: NSError?) -> ()


private class ClosureHolder
{
 let imageClosure:SocialDownloadImageClosure?
 let infoClosure:SocialDownloadInformationClosure?

 init(infoClosure:SocialDownloadInformationClosure)
 {
    self.infoClosure = infoClosure
 }
 init(imageClosure:SocialDownloadImageClosure)
 {
    self.imageClosure = imageClosure
 }
}

然后我像这样制作字典：

var requests = Dictionary<String,ClosureHolder>()

现在要在字典中添加一个闭包，只需执行以下操作：

self.requests["so:c0.onSelection"] = ClosureHolder(completionHandler)

Answer 3

Connor是正确的，我确实尝试了很多方法在同一个字典中存储变量和闭包，但是我失败了并且无法解析它，swift反编译器会抛出错误：

"Command failed due to signal: Segmentation fault: 11" (the hell is it?!)

例如：

//This won't work
var params:[String: Any] = ["x":100, "onFoundX": {println("I found X!")}]
if var onFoundX: (()->Void) = params["onFoundX"] as? (()->Void) {
    onFoundX()
}

//This should work by separate into 2 dictionaries and declare the "typealias" obviously
var params:[String: Any] = ["x":"100"}]
var events:[String: (()->Void)] = ["onFoundX": {println("I found X!")]

if var onFoundX: (()->Void) = events["onFoundX"] as? (()->Void) {
    onFoundX() // "I found X!"
}

if var x = events["x"] as? String {
    println(x) // 100
}

我希望Swift能够在未来实现这一目标。

干杯！

Answer 4

这个简单的例子帮助我理解了一点：

//Init dictionary with types (i.e. String type for key, Closure type for value):
var myDictionary: [String: ()->(String)] = [:]

//Make a closure that matches the closure signature above and assign to variable (i.e. no parameter and returns a String):
let sayHello: () -> (String) = {
    return "Hello!"
}

//Add closure to dictionary with key:
myDictionary["myFunc"] = sayHello

//Access closure by known key and call it:
myDictionary["myFunc"]!() //"Hello!"

Swift - 在词典中存储闭包

4 个答案: