我有一对多的关系,看起来像这样,
我已将模型类设置在一个文件中以匹配:
import CoreData
import Foundation
class Board: NSManagedObject {
@NSManaged var boardColor: String
@NSManaged var boardCustomBackground: AnyObject?
@NSManaged var boardID: String
@NSManaged var boardName: String
@NSManaged var lists: NSSet
}
class List: NSManagedObject {
@NSManaged var listID: String
@NSManaged var listName: String
@NSManaged var board: Board
}
因为我从多个JSON端点获取数据,所以我必须单独从我的板上保存我的列表。 我想要做的是为具有匹配的boardID 的电路板创建/更新列表。
这是我多次尝试后的位置:
func saveList(boardID: String, listName: String, listID: String) {
let request = NSFetchRequest(entityName: "Board")
var error: NSError? = nil
request.predicate = NSPredicate(format: "boardID like %@", boardID)
let results: NSArray = context.executeFetchRequest(request, error: &error)
if results.count > 0 {
for result in results {
let board = result as Board
let list = NSEntityDescription.insertNewObjectForEntityForName("List", inManagedObjectContext: context) as List
println(" want to save \(listName) in \(board.boardName)")
board.lists.addListObject(lists)
list.listName = listName
list.listID = listID
}
}
}
基于Defining CoreData Relationships in Swift和this,我试图实现@Kenenle对板内定义列表对象的回答:
import Foundation
extension Board {
func addListObject(value:List) {
var items = self.mutableSetValueForKey("lists");
items.addObject(value)
}
func removeListObject(value:List) {
var items = self.mutableSetValueForKey("lists");
items.removeObject(value)
}
}
但是,我在board.lists.addListObject(lists)
处遇到以下错误:
'NSSet'没有名为'addListObject'的成员
而不是board.lists.addListObject(lists)
,我也尝试了board.lists.listName = listName
Obj-C example所暗示的,但遗憾的是,这也不起作用。
(另外,println
输出正确指定了正确的电路板和列表。)
提前致谢!
答案 0 :(得分:30)
在一对多关系中,设置“一对一”方向更容易 反向关系,在你的情况下只是
list.board = board
这样实际上不需要扩展方法。
答案 1 :(得分:6)
您应该在addListObject(...)
对象上调用board
:
board.addListObject(list) // notice that we pass just one object
另外,如果您希望能够向特定board
对象添加一组列表,则可以使用接受一组对象的方法增强Board
类扩展:
func addList(values: NSSet) {
var items = self.mutableSetValueForKey("lists");
for value in values {
items.addObject(value)
}
}
func removeList(values: NSSet) {
var items = self.mutableSetValueForKey("lists");
for value in values {
items.removeObject(value)
}
}
答案 2 :(得分:3)
如果你定义:
@NSManaged var lists: Set<List>
然后你可以这样做:
board.lists.insert(list)