Question

我创建了一个可以存储项目的页面。但是当我尝试添加一个项目并在创建后立即删除它时，id是未定义的。当我在插入项目后刷新页面时，我可以毫无问题地删除该项目。

我需要找到一种方法，在我将洞穴内容推送到json数组之前，我可以从数据库中获取项目ID。

<form ng-submit="submit('Bedrijf')">
        <input type="text" ng-model="title" placeholder="Add item" />
        <input type="text" ng-model="searchText" placeholder="Search for item"/>
        <button type="submit">Submit</button>
    </form>
    <br/>
    <ul>
        <li ng-repeat="project in projects | orderBy:'id':true | filter:statusFilterOpen | filter:searchText | limitTo: 10">
            <a href="projects/[[project.id]]">[[project.title]]</a>
            <a class="btn" ng-click="remove(project.id)">Delete</a>
        </li>
    </ul>


project.controller("PrjctCtrl", function($scope, $http, $timeout) {

$http.get('js/projects.json').
    success(function(data, status, headers, config) {

        $scope.projects = data;

        $scope.statusFilterOpen = function (project) {
            return project.status < 100;
        };

        $scope.statusFilterClosed = function (project) {
            return project.status === 100;
        };


    }).
    error(function(data, status, headers, config) {
        // log error
    });


$scope.submit = function($company) {
    data = {
        title: $scope.title,
        company: $company,
        status: 0
    };

    $http.post('add-projects', data).success(function(post) {
        console.log(post)
        $scope.projects.push(post);
    });
};

$scope.remove = function(id) {
    $http.post('delete-project/' + id).success(function(test) {
        $scope.projects.splice($scope.projects.indexOf(id),1);

        if(popupService.showPopup('Really delete this?')){
            movie.$delete(function(){
                $window.location.href='';
            });
        }
    });


}

}）;

我使用laravel将所有内容存储在数据库中。

public function store()
{
    $content = Input::json()->all();

    DB::table('projects')->insert(
        $array = array(
            'title' => $content['title'],
            'active' => '1',
            'company' => 'Bedrijf',
            'id' => 'test'
        )
    );
    return $array;
}

    public function destroy($id) {

    $project = Projects::find($id);
    $project->delete();

    return 'ok';
}

Answer 1

只是查看你的代码，delete语句的格式与其他语句的格式不同。

<a href="projects/[[project.id]]">[[project.title]]</a>
<a class="btn" ng-click="remove(project.id)">Delete</a>

应该是：

<a href="projects/[[project.id]]">[[project.title]]</a>
<a class="btn" ng-click="remove([[project.id]])">Delete</a>

创建后直接删除项目

1 个答案: