Question

我有两个型号买单和卖单。在我的订单屏幕上，我有一个显示所有订单的部分，即买卖订单的组合。

我通过以下命令获取所有订单的清单：

def self.get_orders(p_uid)
    b = Buyorder.where(“user_id=?”,p_uid).all.to_a
    a = Sellorder.where(“user_id=?”,p_uid).all.to_a
    return a+b
end

控制器执行：

@orders = Order.get_orders(session[:user_id])

在我看来，我会做以下事情：

<% for o in @orders %>
    <tr><td> <%= link_to 'Delete', o, data: {confirm: 'Are you sure?'} , :method => :delete %></td> </tr>
<% end %>

我的routes.rb显示：

resources :orders
resources :buyorders
resources :sellorders

控制器买方控制器和卖方控制器都有

def destroy
    ….
end

但是我收到以下错误：

No route matches {:action=>"show", :controller=>"buyorders", :id=>nil} missing required keys: [:id]

destroy方法如下所示：

def destroy
    Buyorder.where("id=? and user_id=?",params[:id],session[:user_id]).destroy_all
    flash[:info] = 'Order has been deleted'
    redirect_to main_index_path()
end

并且rake：路线显示：

            buyorders GET    /buyorders(.:format)                 buyorders#index
                      POST   /buyorders(.:format)                 buyorders#create
         new_buyorder GET    /buyorders/new(.:format)             buyorders#new
        edit_buyorder GET    /buyorders/:id/edit(.:format)        buyorders#edit
             buyorder GET    /buyorders/:id(.:format)             buyorders#show
                      PATCH  /buyorders/:id(.:format)             buyorders#update
                      PUT    /buyorders/:id(.:format)             buyorders#update
                      DELETE /buyorders/:id(.:format)             buyorders#destroy

为什么？

PS：谁在降级所有答案以及问题？这是危险的。如果您认为这个问题很愚蠢，那么请提供一个有效的答案，我将非常乐意接受降级。

解决方案：

self.get_orders的原始代码如下所示：

a = Buyorder.select('price,open_quantity').where("user_id=?",p_uid).all.to_a
b = Sellorder.joins('currency').select('id,currency1_id,currency2_id,ostatus,price,open_quantity').where("user_id=?",p_uid).all.to_a

一旦我使两行返回与

相同的结果

a = Buyorder.joins('currency').select('id,currency1_id,currency2_id,ostatus,price,open_quantity').where("user_id=?",p_uid).all.to_a
b = Sellorder.joins('currency').select('id,currency1_id,currency2_id,ostatus,price,open_quantity').where("user_id=?",p_uid).all.to_a

错误消失了。

换句话说，如果组合两个数组，请确保它们返回的列完全相同。

Answer 1

在视图中更新for循环

<tr><td> <%= link_to 'Delete', o, :method => :delete, data: {confirm: 'Are you sure?'} %></td> </tr>

Answer 2

Url助手似乎无法使用您刚构建的阵列的元素构建路径。

试试这个：

if o.is_a?(Buyorder)
  = link_to 'Delete', buyorder_path(id: o.id), data: {confirm: 'Are you sure?'} , :method => :delete
else
  = link_to 'Delete', sellorder_path(id: o.id), data: {confirm: 'Are you sure?'} , :method => :delete
end

RubyOnRails在destroy上抛出“No Route Matches”

2 个答案: