Question

我的example-ajax调用的Json-Response-Body将不会按预期进行deserilise。出于测试目的，我想返回一个空的JSON-Array。

JavaScript: JSON-Ajax-Call

saveFiles: function (files) {
            $.ajax({
                url: "SaveFile.do",
                type: "post",
                data: JSON.stringify(files),
                contentType: "application/json",
                success: function (saved) {
                    showSaveResult(saved);
                }
            });
        },

Java-Controller:        

@RequestMapping(value="/SaveFile.do", method = RequestMethod.POST)
    @ResponseBody public ArrayNode createSaveResult (@RequestBody Data[] entities, BindingResult result, Locale locale){
        ArrayNode jsonReturn = new ArrayNode(jsonNodeFactory);
        return jsonReturn;
}

Request:

[{key:value1},{key:value2}]

Response:

{"array":true,"elements":[],"containerNode":true,"valueAsText":null,"numberType":null,"fields":[],"fieldNames":[],
"null":false,"textValue":null,"booleanValue":false,"long":false,"valueNode":false,"missingNode":false,
"object":false,"pojo":false,"number":false,"integralNumber":false,"floatingPointNumber":false,"int":false,
"double":false,"bigDecimal":false,"bigInteger":false,"textual":false,"boolean":false,"binary":false,
"numberValue":null,"intValue":0,"longValue":0,"bigIntegerValue":0,"doubleValue":0.0,"decimalValue":0,
"binaryValue":null,"valueAsInt":0,"valueAsLong":0,"valueAsDouble":0.0,"valueAsBoolean":false}

相反，响应提供了完整的ArrayNode对象。我该如何解决这个问题？

Answer 1

ArrayNode是杰克逊对阵列中单个元素的表示。如果您只是返回它，那么您将获得ArrayNode的序列化版本，而不是您想要的空数组元素。

您可以返回代表预期数据集的类：

private static class SaveResult {
    String key;
    String value;
}

@ResponseBody public SaveResult[] createSaveResult (@RequestBody Data[] entities, BindingResult result, Locale locale){
    return new SaveResult[0];
}

你也可以手工建立Json并返回字符串，如下所示（How to create this json string using Jackson?）。

我倾向于第一种方法，因为我觉得快速阅读代码会更加明显。

杰克逊对弹簧反应体的反序列化

1 个答案: