Question

我的应用中有一项服务，用于向服务器发送http post请求，称为Communicator。我通常从我的活动绑定它，但现在我需要从广播接收器调用它（因为我需要每分钟向服务器发送一次请求）所以我使用startService(intent)

经过一些调试后，似乎在调用startService(intent)时出现以下错误：

08-04 06:07:10.447: W/ActivityManager(1138): Unable to start service Intent { act=ping_states flg=0x14 cmp=com.example.imhere/.Pinger (has extras) } U=0: not found

这是我的课程，扩展了BroadcastReceiver：

public class Pinger extends BroadcastReceiver{

@Override
public void onReceive(Context context, Intent intent) {
    //start the communicator and request to iterate over locations with true 'here state'
    Log.d("tom.debug", "Pinger class is calling to start the service"); //acording to the log, this part of the code is reached
    /*EDIT - THE ISSUE WAS FOUND HERE - See Imtiyaz's answer*/
    context.startService(intent); //so this is probably the reason I'm seeing the error

    }
}

这是我创建意图的方式（根据这里的问题：How to run a method every X seconds）：

private void startPinging() {
    Date when = new Date(System.currentTimeMillis() + (MINUTE));
    try{
           Intent pingerIntent = new Intent(this.getApplicationContext(), Pinger.class);
           pingerIntent.setAction(getString(R.string.intent_action_ping_states));

           PendingIntent pendingIntent = PendingIntent.getBroadcast(
                this.getApplicationContext(), 
                0,
                pingerIntent,
                PendingIntent.FLAG_CANCEL_CURRENT);

           AlarmManager alarms = (AlarmManager) this.getApplicationContext().getSystemService(
                Context.ALARM_SERVICE);

           alarms.set(AlarmManager.RTC_WAKEUP,
                   when.getTime(),
                   pendingIntent);

           alarmSet = true;

           Log.d("tom.debug", "startPinging: alarmSet is now true");

        } catch(Exception e){
           e.printStackTrace();
        }
}

我认为清单文件也是相关的：

...
<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >

    <receiver android:enabled="true"
        android:exported="false"
        android:name="com.example.imhere.Pinger" >
        <intent-filter>
            <action android:name="@string/intent_action_ping_states" />
        </intent-filter>
    </receiver>

    <service
        android:name="com.example.imhere.Communicator"
        android:enabled="true"
        android:exported="true" >
        <intent-filter>
            <action android:name="@string/intent_action_ping_states" />
        </intent-filter>
    </service>
    ...
</application>
...

Answer 1

你不能像你一样直接启动意图。

以这种方式尝试：

@Override
public void onReceive(Context context, Intent intent) {
    //start the communicator and request to iterate over locations with true 'here state'
    Log.d("tom.debug", "Pinger class is calling to start the service"); //acording to the log, //this part of the code is reached
    //context.startService(intent); //so this is probably the reason I'm seeing the error

    //if some data you want from this broadcast event then you can do like
    // String tempMessage  = intent.getStringExtra("KEY");
    Intent serviceIntent  = new Intent(context , YOUR_SERVICE.class);
    context.startService(serviceIntent  );

}

感谢。

当从broadcastReceiver调用服务时，为什么我“无法启动服务Intent ... not found”？

1 个答案: