假设我有一个文件BookDB.txt,它以下列格式存储数据:
Harry Potter - The Half Blood Prince:J.K Rowling:40.30:10:50
The little Red Riding Hood:Dan Lin:40.80:20:10
Harry Potter - The Phoniex:J.K Rowling:50.00:30:20
Harry Potter - The Deathly Hollow:Dan Lin:55.00:33:790
Little Prince:The Prince:15.00:188:9
Lord of The Ring:Johnny Dept:56.80:100:38
Three Little Pig:Andrew Lim:89.10:290:189
All About Linux:Ubuntu Team:76.00:44:144
Catch Me If You Can:Mary Ann:23.60:6:2
Python for dummies:Jared Loo:15.99:1:10
我想在输出中用(,)替换(:)分隔符。它成功,但从输出中删除换行符。这是我的代码:
TITLE=Potter
OUTPUT=$(cat BookDB.txt | grep $TITLE)
OUTPUT1=$(sed 's/:/, /g' <<< $OUTPUT)
echo $OUTPUT1
我希望我的输出看起来像这样:
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling. 50.00. 30. 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
然而,它看起来像这样:
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50 Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20 Harry Potter - The Deathly Holl
ow, Dan Lin, 55.00, 33, 790
如果有人可以分享如何在输出中保留换行符,我将非常感激!
答案 0 :(得分:9)
只需使用正确的引文:
TITLE=Potter
OUTPUT=$(cat BookDB.txt | grep $TITLE)
OUTPUT1=$(sed 's/:/, /g' <<< "$OUTPUT")
echo "$OUTPUT1"
由于\n
是默认值IFS的一部分,因此不会使用双引号将其删除。
有关引用here
的更多信息答案 1 :(得分:4)
您可以避免cat
并在sed中执行所有操作:
sed -n '/Potter/s/:/, /gp' file
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
答案 2 :(得分:0)
使用awk
。匹配将特定于标题,并且不包括作者的姓名。
awk -F: -v OFS=', ' '$1 ~ /Potter/ { $1 = $1; print }' file
输出:
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
这没有输出:
awk -F: -v OFS=', ' '$1 ~ /Rowling/ { $1 = $1; print }' file
但这会:
awk -F: -v OFS=', ' '$2 ~ /Rowling/ { $1 = $1; print }' file
输出:
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
要与标题和作者匹配,您可以:
awk -F: -v OFS=', ' '$1 ~ /Potter/ && $2 ~ /Rowling/ { $1 = $1; print }' file
或者如果有任何验证匹配:
awk -F: -v OFS=', ' '$1 ~ /Potter/, $2 ~ /Rowling/ { $1 = $1; print }' file