Question

我正在使用loop4j来获取HttpAsync请求。

我正在调用片段中的请求：

RestHttpClientUsage.registerUser(m_context);

这是我的其余客户端代码：

public static void registerUser(Context context) throws JSONException 
{   
    RestHttpClient.get("?Operation=RegisterUser" , params, new JsonHttpResponseHandler() 
    {                   
        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONObject response) 
        {
            ...
        }

        @Override
        public void onFailure(int statusCode, Header[] headers,String responseString, Throwable throwable) 
        {
            ...
        }

    });
}

我的问题是如何从onSuccess / onFailure回调中访问调用片段？

我需要在调用完成后调用我的片段UpdateUI。

我可以以某种方式从上下文对象中获取片段吗？

Answer 1

您可以使用私人BroadcastReceiver来更新用户界面。这里是BroadcastReceiver的声明：

public class MyFragment extends Fragment {
    // Declare UI elements
    private final BroadcastReceiver receiver = new MyBroadcastReceiver();

    // Initialize elements in onCreate

    @Override
    public void onResume() {
        super.onResume();
        IntentFilter filter = new IntentFilter("UPDATE_MY_FRAGMENT");
        getActivity().registerReceiver(receiver, filter);
    }

    @Override
    public void onPause() {
        super.onPause();
        getActivity().unregisterReceiver(receiver);
    }

    private class MyBroadcastReceiver extends BroadcastReceiver {
        @Override
        public void onReceive(Context context, Intent intent) {

            // Read data from intent.getExtras()
            // update UI elements
        }
    }
}

从intent发送registerUser到私人BrodcastReceiver：

public static void registerUser(final Context context) throws JSONException 
{   
    RestHttpClient.get("?Operation=RegisterUser" , params, new JsonHttpResponseHandler() 
    {                   
        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONObject response) 
        {
            Intent intent = new Intent("UPDATE_MY_FRAGMENT");
            // pass data using intent.putExtra based on response
            context.sendBroadcast(intent);
        }

        @Override
        public void onFailure(int statusCode, Header[] headers,String responseString, Throwable throwable) 
        {
            Intent intent = new Intent("UPDATE_MY_FRAGMENT");
            // pass data using intent.putExtra based on response
            context.sendBroadcast(intent);
        }

    });
}

Answer 2

您可以做的只是将响应（在这种情况下为json对象/数组）序列化为全局变量或POJO，然后您可以从loop4j上下文外部调用UI。

这对你有意义吗？

Answer 3

因为它在UI线程上提供响应（你在UI上创建请求）我认为你可以这样做：

callingFragment.this.getActivity().getSupportFragmentManager().findFragmentBytag("your calling fragment tag").updatUI;

在异步http请求之后更新Fragment UI

3 个答案: