Question

您好我正在尝试编写一个查询，该查询将返回客户的每日客户记录数（过去7天）

给出一个包含以下重要字段的表

ClientId,    ProcessTime,

id喜欢使用clientId生成一个表，最后7天生成列标题0 - 7（包括今天）以及当天处理的记录

ClientId, 0, 1, 2, 3, 4, 5, 6, 7

我提出了以下查询，让我接近

Select ClientId, Count(Id) as [Count], max(DATEDIFF(DAY,ProcessTime,GETDATE())) as [Day]
from CallRecords
WHERE DATEDIFF(DAY,ProcessTime,GETDATE()) <= 7
group by ClientId, Dateadd(day, Datediff(day, 0, ProcessTime), 0)
order by 1, 2

产生

ClientId Count Day 
1        60    0
1        4707  1
1        11613 2

然而我，我不知道如何将这些结果操作为一种格式，我得到一个客户列表和最后7天的结果作为列

有什么想法吗？

Answer 1

SELECT ClientID 
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 1 THEN 1 ELSE NULL END) AS [Sunday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 2 THEN 1 ELSE NULL END) AS [Monday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 3 THEN 1 ELSE NULL END) AS [Tuesday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 4 THEN 1 ELSE NULL END) AS [Wednesday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 5 THEN 1 ELSE NULL END) AS [Thursday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 6 THEN 1 ELSE NULL END) AS [Friday]
      ,COUNT(CASE WHEN DATEPART(WEEKDAY,ProcessTime) = 7 THEN 1 ELSE NULL END) AS [Saturday]
FROM CallRecords
WHERE ProcessTime >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) - 7, 0) 
GROUP BY ClientID

Answer 2

你想要的是pivot，SQLServer本身支持：

select ClientId, [0], [1], [2], [3], [4], [5], [6], [7]
from (select ClientId, DATEDIFF(DAY,ProcessTime,GETDATE()) days
    from CallRecords
    where DATEDIFF(DAY,ProcessTime,GETDATE()) <= 7) t
pivot (count(days) for days in ([0], [1], [2], [3], [4], [5], [6], [7])) pt

SQLFiddle

Answer 3

Pivot是实现此方案的方法。以下是Microsofts数据透视文档Microsoft PIVOT的链接。要查找星期几，您应使用DatePart函数Microsoft DatePart Function

select ClientId as 'Client', [1], [2], [3], [4], [5], [6], [7] from (
    select ClientId, Id, CAST(DatePart(dw,ProcessTime) as int) as [DayOfWeek]
    from CallRecords
) as SourceTable
PIVOT (
    COUNT(Id)
    FOR [DayOfWeek] IN ([1], [2], [3], [4], [5], [6], [7])
) as pvt

Checkout this SQLFiddle

clientId每周返回所有记录的计数

3 个答案: