Question

我想使用$ .POST或$ .AJAX实现创建（INSERT）屏幕。

注意：代码工作正常，没有AJAX调用..已经存在..现在我需要做ajax调用并保存而不回发。我在下面写了代码：

在提交点击事件后面是代码：

$.ajax(
      {
          url: '@Url.Action("CreateProduct","ProductManagement")',
          dataType: 'json',
          contentType: 'application/json; charset=utf-8',
          type: 'post',
          data:   $('frm').serialize(),
          success: function () { alert('s'); },
          error: function (e1, e2, e3) { alert(e2); alert(e1 + ' ' + e2 + ' ' + e3); alert('failure event'); }
      }
    );
});

在服务器端：

[HttpPost]
public JsonResult CreateProduct(FormCollection frm)
{
    manager.ProductManager m = new manager.ProductManager();
    // m.InsertProduct(new common.DTO.ProductDTO() { Id = id, ProductName = ProductName, Description = Description, Cost = cost, ProductTypeId = 5 });
    return Json("'result':'success'", JsonRequestBehavior.AllowGet);
}

问题是，每次调用操作但在frm参数参数上找不到数据。我也试图保持 - 查看模型ProductViewModel vm作为参数，但它不起作用..只给我空值。而且，在ajax电话中，它取得了成功但是。只是问题在控制器的行动中没有发布。

Html如下：

  @using (Html.BeginForm("CreateProduct", "ProductManagement", FormMethod.Post, new { id = "frm" }))
    {
@Html.AntiForgeryToken()
@Html.ValidationSummary(true)

<fieldset>
    <legend>ProductViewModel</legend>
    <div id="CreateDiv">
        <div class="editor-label">
            @Html.LabelFor(model => model.ProductName)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.ProductName)
            @Html.ValidationMessageFor(model => model.ProductName)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Cost)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Cost)
            @Html.ValidationMessageFor(model => model.Cost)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Description)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Description)
            @Html.ValidationMessageFor(model => model.Description)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.ProductTypeId)
        </div>
        <div class="editor-field">
            @Html.DropDownList("ProductTypeId", "Choose item")
            @Html.ValidationMessageFor(model => model.ProductTypeId)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.ProductTypeName)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.ProductTypeName)
            @Html.ValidationMessageFor(model => model.ProductTypeName)
        </div>
    </div>
    <p>
        <input type="submit" value="Create" id="btnSubmit" />
    </p>

</fieldset>
 }

 <div>
 @Html.ActionLink("Back to List", "Index")
 </div>

请指导我这里有什么问题。

谢谢

Answer 1

对于id Selector，您必须使用＆＃34;＃＆＃34;与id。

这将有效：

$.ajax(
  {
      url: '@Url.Action("CreateProduct","ProductManagement")',
      dataType: 'json',
      contentType: 'application/json; charset=utf-8',
      type: 'post',
      data:   $('this').serialize(), OR  $('#frm').serialize(),   <-----------------
      success: function () { alert('s'); },
      error: function (e1, e2, e3) { alert(e2); alert(e1 + ' ' + e2 + ' ' + e3); alert('failure event'); }
  }
 );

或试试这个：

var form = $('#frm');
$.ajax({
 cache: false,
 async: true,
 dataType: 'json',
 contentType: 'application/json; charset=utf-8',
 type: "POST",
 url: form.attr('action'),
 data: form.serialize(),
 success: function (data) {
 alert(data);
   }
 });

Answer 2

您忘记添加ID选择器：

$.ajax(
      {
          url: '@Url.Action("CreateProduct","ProductManagement")',
          dataType: 'json',
          contentType: 'application/json; charset=utf-8',
          type: 'post',
          data:   $('#frm').serialize(),                      // $('#frm');
          success: function () { alert('s'); },
          error: function (e1, e2, e3) { alert(e2); alert(e1 + ' ' + e2 + ' ' + e3); alert('failure event'); }
      }
    );

Answer 3

如果表单的ID为frm，则应引用如下

data:   $("#frm").serialize(),

如何在MVC中使用JQUERY AJAX将viewmodel发布到action方法

3 个答案: