Question

我想打印出返回函数的值，我的主要目的是从不同的文件中调用函数，我已经用不同的函数做了好几次，但是这似乎没有用，我不能算出来。请帮忙。

swifty.php

    include_once('core/init.php');
    $errorno = 'Please contact the administrator, Quoting err no : q2913, Q Issues referring to: ' . mysqli_error($con);

    function getStatus_update() {
        $user_id = (int) $user_data['id'];
        $result = mysqli_query($con, "SELECT * FROM users_status WHERE `user_id` = '$user_id` ORDER BY `date_posted` DESC'");
        $update = array();
        while ($row = mysqli_fetch_array($result)) {
            $update[] = $row;
        }return $update;
    }

user.php的

<?php
include_once 'swifty.php';
$rand = getStatus_update();

        foreach ($rand as $k => $v) {
            var_dump($v['status']);
        }

没有任何反应，没有错误消息，也没有返回任何值。

Answer 1

$user_data函数

中的$con和getStatus_update()都不在scope

include_once('core/init.php');
$errorno = 'Please contact the administrator, Quoting err no : q2913, Q Issues referring to: ' . mysqli_error($con);

function getStatus_update($con, $user_data) {
    $user_id = (int) $user_data['id'];
    $result = mysqli_query($con, "SELECT * FROM users_status WHERE `user_id` = '{$user_id}' ORDER BY `date_posted` DESC");
    $update = array();
    while ($row = mysqli_fetch_array($result)) {
        $update[] = $row;
    }
    return $update;
}

和

$rand = getStatus_update($con, $user_data);

foreach ($rand as $k => $v) {
    var_dump($v['status']);
}

如果您刚刚开始学习PHP，那么也要学会在SQL查询中使用绑定变量

Answer 2

您可能还想设置包含路径

PHP函数调用不起作用

2 个答案: