Question

通过cmd运行此代码时出现此错误。错误告诉它在行中没有。 7但无法找到。

var express = require('express'),
filter = express(),
server = require('http').createServer(filter),
io = require('socket.io').listen(server),
mongoose = require('mongoose'),

server.listen(1149, '127.0.0.1');
console.log('Server running at http://127.0.0.1:1149/');

mongoose.connect('mongodb://localhost/chat', function(err){
    if(err){
        console.log(err);
    } else{
        console.log('Connected to mongodb!');
    }
});

var filter_CheckBoxSchema = mongoose.Schema({
category : { type: Boolean, default: false },
created: {type: Date, default: Date.now}
});

我收到错误：

C:\node\people discovery app\filter.js:7
server.listen(1149, '127.0.0.1');
      ^
SyntaxError: Unexpected token .
    at Module._compile (module.js:439:25)
    at Object.Module._extensions..js (module.js:474:10)
    at Module.load (module.js:356:32)
    at Function.Module._load (module.js:312:12)
    at Function.Module.runMain (module.js:497:10)
    at startup (node.js:119:16)
    at node.js:906:3

Answer 1

从第一行开始的变量声明永远不会完成，因此声明：

server.listen(1149, '127.0.0.1');

被视为变量声明，而在此处它不是有效声明。

要解决此问题，您可以使用var从第一行开始填写;语句，例如：

var express = require('express'),
filter = express(),
server = require('http').createServer(filter),
io = require('socket.io').listen(server),
mongoose = require('mongoose'); // <-- Notice the ';' here

server.listen(1149, '127.0.0.1');
console.log('Server running at http://127.0.0.1:1149/');
...

运行时获取意外令牌

1 个答案: