登录时我遇到上述错误。使用security.yml中的属性选项,它正在工作。我在我的实体类中添加了@ORM\Entity(repositoryClass="versionR\userBundle\Entity\UserRepository")
行,dobule检查了路径,清除了缓存但没有运气。
用户实体类
<?php
namespace versionR\userBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
//use Symfony\Component\Security\Core\Role\Role;
use Symfony\Component\Security\Core\User\UserInterface;
/**
* User
*
* @ORM\Table(name="user")
* @ORM\Entity(repositoryClass="versionR\userBundle\Entity\UserRepository")
*/
class User implements UserInterface, \Serializable
{
/**
* @var string
*
* @ORM\Column(name="username", type="string", length=40, nullable=false)
*/
private $username;
/**
* @var string
*
* @ORM\Column(name="password", type="string", length=255, nullable=false)
*/
private $password;
/**
* @var string
*
* @ORM\Column(name="email", type="string", length=255, nullable=false)
*/
private $email;
/**
* @var string
*
* @ORM\Column(name="address", type="string", length=255, nullable=false)
*/
private $address;
/**
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $id;
/**
* @var \Doctrine\Common\Collections\Collection
*
* @ORM\ManyToMany(targetEntity="versionR\userBundle\Entity\Role", inversedBy="user")
* @ORM\JoinTable(name="user_role",
* joinColumns={
* @ORM\JoinColumn(name="user_id", referencedColumnName="id")
* },
* inverseJoinColumns={
* @ORM\JoinColumn(name="role_id", referencedColumnName="id")
* }
* )
*/
private $role;
/**
* Constructor
*/
public function __construct()
{
$this->role = new \Doctrine\Common\Collections\ArrayCollection();
}
/**
* @param string $address
*/
public function setAddress($address)
{
$this->address = $address;
}
/**
* @return string
*/
public function getAddress()
{
return $this->address;
}
/**
* @param string $email
*/
public function setEmail($email)
{
$this->email = $email;
}
/**
* @return string
*/
public function getEmail()
{
return $this->email;
}
/**
* @param int $id
*/
public function setId($id)
{
$this->id = $id;
}
/**
* @return int
*/
public function getId()
{
return $this->id;
}
/**
* @param string $password
*/
public function setPassword($password)
{
$this->password = $password;
}
/**
* @return string
*/
public function getPassword()
{
return $this->password;
}
/**
* @param string $username
*/
public function setUsername($username)
{
$this->username = $username;
}
/**
* @return string
*/
public function getUsername()
{
return $this->username;
}
/**
* @param \Doctrine\Common\Collections\Collection $role
*/
public function setRole($role)
{
$this->role->add($role);
}
/**
* @return \Doctrine\Common\Collections\Collection
*/
public function getRole()
{
return $this->role;
}
/**
*/
public function serialize()
{
return serialize(array(
$this->id,
$this->username,
$this->password,
// see section on salt below
// $this->salt,
));
}
/**
*/
public function unserialize($serialized)
{
list (
$this->id,
$this->username,
$this->password,
// see section on salt below
// $this->salt
) = unserialize($serialized);
}
/**
* Returns the roles granted to the user.
*/
public function getRoles()
{
return $this->role->toArray();
}
/**
*/
public function getSalt()
{
return null;
}
/**
*/
public function eraseCredentials()
{
// TODO: Implement eraseCredentials() method.
}
}
用户存储库类
<?php
namespace versionR\userBundle\Entity;
use Doctrine\ORM\EntityRepository;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
/**
* UserRepository
*
* This class was generated by the Doctrine ORM. Add your own custom
* repository methods below.
*/
class UserRepository extends EntityRepository implements UserProviderInterface
{
/**
* @param string $username
* @return \versionR\userBundle\Entity\User
*/
public function loadUserByUsername($username)
{
return $this->findOneBy(array('username' => $username));
}
public function refreshUser(UserInterface $user)
{
$class = get_class($user);
if (!$this->supportsClass($class)) {
throw new UnsupportedUserException(
sprintf(
'Instances of "%s" are not supported.',
$class
)
);
}
return $this->find($user->getId());
}
public function supportsClass($class)
{
return $this->getEntityName() === $class
|| is_subclass_of($class, $this->getEntityName());
}
}
这两个类都在Entity目录中。有任何建议可以解决这个问题。我正在使用symfony 2.5.2