我想从GUI线程设置HandlerThread。然后一段时间后,当在GUI上单击一个按钮时,它运行callHello(),然后将消息发送到驻留在非GUI线程上的HelloLogger对象,该对象异步记录" Hello World"。我已经尝试过很多东西,有些是无限期阻塞,有些是从不接收消息等等。下面的代码或多或少都和我一样接近,请有人修改它吗?
public class HandlerThreadExample {
private MyHandlerThread mMyHandlerThread;
private Looper mLooper;
private Handler mHandler;
public HandlerThreadExample(){
mMyHandlerThread = new MyHandlerThread();
mMyHandlerThread.start();
mLooper = mMyHandlerThread.getLooper();
}
public void callHello() {
mHandler.sendEmptyMessage(1);
}
private class MyHandlerThread extends HandlerThread {
private HelloLogger mHelloLogger;
private Handler mHandler;
public MyHandlerThread() {
super("The MyHandlerThread thread", HandlerThread.NORM_PRIORITY);
}
public void run (){
mHelloLogger = new HelloLogger();
mHandler = new Handler(getLooper()){
public void handleMessage(Message msg){
mHelloLogger.logHello();
}
};
super.run();
}
}
private class HelloLogger {
public HelloLogger (){
}
public void logHello(){
Log.d("HandlerThreadExample", "Hello World");
}
}
}
找到最好的例子:
至少现在我可以关闭该死的标签
解决方案由pskink提供帮助
public class HandlerThreadExample2 {
private static int MSG_START_HELLO = 0;
private static int MSG_HELLO_COMPLETE = 1;
private HandlerThread ht;
private Handler mHtHandler;
private Handler mUiHandler;
private boolean helloReady = false;
public HandlerThreadExample2(){
ht = new HandlerThread("The new thread");
ht.start();
Log.d(App.TAG, "UI: handler thread started");
mUiHandler = new Handler(){
public void handleMessage(Message msg){
if (msg.what == MSG_HELLO_COMPLETE){
Log.d(App.TAG, "UI Thread: received notification of sleep completed ");
helloReady = true; }
}
};
mHtHandler = new Handler(ht.getLooper()){
public void handleMessage (Message msg){
if (msg.what == MSG_START_HELLO){
Log.d(App.TAG, "handleMessage " + msg.what + " in " + Thread.currentThread() + " now sleeping");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Log.d(App.TAG, "Woke up, notifying UI thread...");
mUiHandler.sendEmptyMessage(MSG_HELLO_COMPLETE);
}
}
};
}
public void sendLongHello(){
if (helloReady){
Log.d(App.TAG, "sending hello " + Thread.currentThread());
mHtHandler.sendEmptyMessage(MSG_START_HELLO);
helloReady = false;
} else {
Log.e(App.TAG, "Cannot do hello yet - not ready");
}
}
}
答案 0 :(得分:51)
这是一个有效的例子:
HandlerThread ht = new HandlerThread("MySuperAwesomeHandlerThread");
ht.start();
Handler h = new Handler(ht.getLooper()) {
public void handleMessage(Message msg) {
Log.d(TAG, "handleMessage " + msg.what + " in " + Thread.currentThread());
};
};
for (int i = 0; i < 5; i++) {
Log.d(TAG, "sending " + i + " in " + Thread.currentThread());
h.sendEmptyMessageDelayed(i, 3000 + i * 1000);
}
<强>更新强>:
制作两个类别字段:
Handler mHtHandler;
Handler mUiHandler;
试试这个:
HandlerThread ht = new HandlerThread("MySuperAwsomeHandlerThread");
ht.start();
Callback callback = new Callback() {
@Override
public boolean handleMessage(Message msg) {
if (msg.what == 0) {
Log.d(TAG, "got a meaasage in " + Thread.currentThread() + ", now sleeping... ");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Log.d(TAG, "woke up, notifying ui thread...");
mUiHandler.sendEmptyMessage(1);
} else
if (msg.what == 1) {
Log.d(TAG, "got a notification in " + Thread.currentThread());
}
return false;
}
};
mHtHandler = new Handler(ht.getLooper(), callback);
mUiHandler = new Handler(callback);
mHtHandler.sendEmptyMessageDelayed(0, 3000);
您当然可以摆脱Callback
接口并使用重写的handleMessage
方法创建两个处理程序...
答案 1 :(得分:1)
您看到的问题是因为您的外部类正在使用私有mHandler字段,因此您的HandlerThread也是如此。外部类字段未初始化。你不需要内部mHandler。在调用start()之后,外部类可以从你抓住的looper中创建一个处理程序。