Question

我有一个文本框，当用户在文本框中输入任意数字（比如3）时，应该生成许多随机数。这是我到目前为止所做的，但它为所有3个生成相同的随机数（或者和用户输入的一样多）记录。

protected void Page_Load(object sender, EventArgs e)
    {
        for (Int32 x = 0; x <= 50; x++)
        {
            txtRandomNumber.Text = GetRandomString(x);

        }

    }
    public string GetRandomString(int seed)
    {

        const string alphabet = "R";


        Random rnd = new Random((seed + DateTime.Now.Millisecond));


        string result = rnd.Next(10000, 99999).ToString();



        string alpha = alphabet.Substring(rnd.Next(alphabet.Length - 1));


        int replacementIndex = rnd.Next(0);
        result = result.Remove(replacementIndex, 1).Insert(replacementIndex, alpha);


        return result;
    }

    protected void btnSave_Click(object sender, EventArgs e)
    {
        for (int i = 1; i <= int.Parse(txtNoOfPin.Text); i++)
        {
            if (i == 1)
            {
                string strConnection = ConfigurationManager.ConnectionStrings["ReliableLife"].ToString();
                SqlConnection con = new SqlConnection(strConnection);
                string sqlQuery = "insert into AllotPin(NoOfPin,PinNumber) values(@NoOfPin,@PinNumber)";
                con.Open();
                SqlCommand cmd = new SqlCommand(sqlQuery, con);

                cmd.Parameters.AddWithValue("@NoOfPin", int.Parse(txtNoOfPin.Text));

                cmd.Parameters.AddWithValue("@PinNumber", txtRandomNumber.Text);

                cmd.ExecuteNonQuery();

            }
            else
            {
                string r_no = "";

                for (Int32 x = 0; x <= 50; x++)
                {
                    r_no = GetRandomString(x);
                    //Response.Write(GetRandomString(x) + "<br />");
                }


                string strConnection = ConfigurationManager.ConnectionStrings["ReliableLife"].ToString();
                SqlConnection con = new SqlConnection(strConnection);
                string sqlQuery = "insert into AllotPin(NoOfPin,PinNumber) values(@NoOfPin,@PinNumber)";
                con.Open();
                SqlCommand cmd = new SqlCommand(sqlQuery, con);

                cmd.Parameters.AddWithValue("@NoOfPin", int.Parse(txtNoOfPin.Text));

                cmd.Parameters.AddWithValue("@PinNumber", txtRandomNumber.Text);

                cmd.ExecuteNonQuery();

            }
        }
    }

请帮助，谢谢

Answer 1

尝试将随机数添加到文本框

for (Int32 x = 0; x <= 50; x++)
{
    txtRandomNumber.Text  = x +" "+ GetRandomString(x) +" "+ txtRandomNumber.Text;
}

该程序有一些冗余，但它会根据您的要求生成随机数。

Answer 2

感谢您的帮助。我在代码的else部分解决了这个问题：

for (Int32 x = 0; x <= 50; x++)
                {
                    r_no = GetRandomString(x);
                    txtRandomNumber.Text = r_no;

                }

根据需要输出。

为文本框中输入的文本生成随机数

2 个答案: