我们已经整合了yii身份验证加密规则。在登录页面中,提交后 表单,它显示以下错误消息显示
致命错误:在第13行的D:\ wamp \ www \ onlinetest \ protected \ components \ UserIdentity.php中调用未定义的方法LoginForm :: model()
这是控制器代码
public function actionLogin()
{
$model=new LoginForm;
// if it is ajax validation request
if(isset($_POST['ajax']) && $_POST['ajax']==='login-form')
{
echo CActiveForm::validate($model);
Yii::app()->end();
}
// collect user input data
if(isset($_POST['LoginForm']))
{
$model->attributes=$_POST['LoginForm'];
// validate user input and redirect to the previous page if valid
if($model->validate() && $model->login())
$this->redirect(Yii::app()->user->returnUrl);
}
// display the login form
$this->render('login',array('model'=>$model));
}
这是登录表单模型
class LoginForm extends CFormModel
{
public $username;
public $password;
public $rememberMe;
private $_identity;
public function tableName()
{
return 'tbl_login';
}
public function authenticate($attribute,$params)
{
if(!$this->hasErrors()) // we only want to authenticate when no input errors
{
$identity=new UserIdentity($this->username,$this->password);
$identity->authenticate();
switch($identity->errorCode)
{
case UserIdentity::ERROR_NONE:
Yii::app()->user->login($identity);
break;
case UserIdentity::ERROR_USERNAME_INVALID:
$this->addError('username','Username is incorrect.');
break;
default: // UserIdentity::ERROR_PASSWORD_INVALID
$this->addError('password','Password is incorrect.');
break;
}
}
}
public function login()
{
if($this->_identity===null)
{
$this->_identity=new UserIdentity($this->username,$this->password);
$this->_identity->authenticate();
}
if($this->_identity->errorCode===UserIdentity::ERROR_NONE)
{
$duration=$this->rememberMe ? 3600*24*30 : 0; // 30 days
Yii::app()->user->login($this->_identity,$duration);
return true;
}
else
return false;
}
}
以下是组件
中的useridentity.phpclass UserIdentity extends CUserIdentity
{
private $_id;
public function authenticate()
{
$record=LoginForm::model()->findByAttributes(array('VarUser_type'=>$this->username)); // here I use Email as user name which comes from database
if($record===null)
{
$this->_id='user Null';
$this->errorCode=self::ERROR_USERNAME_INVALID;
}
else if($record->E_PASSWORD!==$this->password) // here I compare db password with passwod field
{ $this->_id=$this->username;
$this->errorCode=self::ERROR_PASSWORD_INVALID;
}
else
{
$this->_id=$record['VarUser_type'];
$this->setState('title', $record['VarUser_type']);
$this->errorCode=self::ERROR_NONE;
}
return !$this->errorCode;
}
public function getId() // override Id
{
return $this->_id;
}
}
如何解决此问题?如果你知道帮助我
答案 0 :(得分:1)
你可以不使用
$record=LoginForm::model()->findByAttributes(array('VarUser_type'=>$this->username));
因为LoginForm扩展了CFormModel
对于数据库检索,它应该扩展CActiveRecord
看到这个
你的模型应该是这样的
class Users extends CActiveRecord
{
/**
* Returns the static model of the specified AR class.
* @return Users the static model class
*/
private $_identity;
public static function model($className=__CLASS__)
{
return parent::model($className);
}
/**
* @return string the associated database table name
*/
public function tableName()
{
return 'users';
}
/**
* @return array validation rules for model attributes.
*/
public function rules()
{
// NOTE: you should only define rules for those attributes that
// will receive user inputs.
return array(
array(' password, user_name,' , 'required', 'on'=>'login' ),
array('user_id, last_name, first_name, address1, address2, city, pincode, state_id, country_id, phone, fax, email, created_date, updated_date, last_login, company_name, tour_id, password, user_name, last_login_from, gender, is_session_on, status, memo, cell, role_type_id, group_contract_template_id, group_policy_id, billing_contact, billing_phone, billing_address, billing_email, after_hours_phone', 'safe', 'on'=>'search'),
);
}
/**
* @return array relational rules.
*/
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
);
}
public function login( $id, $password = "" )
{
$this->_identity = new UserIdentity($username = $id ,$password);
$this->_identity->authenticate();
//Yii::app()->user->login($this->_identity,3600*24*30);
if(Yii::app()->user->login($this->_identity,0*0*0))
{
//echo $this->_identity->errorMessage;
return true;
}
else
{
Yii::app()->user->setState('error', $this->_identity->errorMessage);
return false;
}
}
/**
* @return array customized attribute labels (name=>label)
*/
public function attributeLabels()
{
return array(
'user_id' => 'User',
'last_name' => 'Last Name',
'first_name' => 'First Name',
'address1' => 'Address1',
'email' => 'Email',
);
}
/**
* Retrieves a list of models based on the current search/filter conditions.
* @return CActiveDataProvider the data provider that can return the models based on the search/filter conditions.
*/
public function search()
{
// Warning: Please modify the following code to remove attributes that
// should not be searched.
$criteria=new CDbCriteria;
$criteria->compare('user_id',$this->user_id,true);
$criteria->compare('last_name',$this->last_name,true);
$criteria->compare('first_name',$this->first_name,true);
$criteria->compare('email',$this->billing_address,true);
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
));
}
}
答案 1 :(得分:0)
您没有包含模型方法的代码
public static function model($className=__CLASS__)
{
return parent::model($className);
}
在您的模型类中
答案 2 :(得分:0)
您的UserIdentity类方法身份验证不正确。请参阅下面的代码以了解具体方法。
public function authenticate()
{
$record=YourUserModel::model()->find(array(
'condition'=>'VarUser_type =:username',
'params'=>array(':username'=>$this->username)
));
if($record===null)
{
$this->_id='user Null';
$this->errorCode=self::ERROR_USERNAME_INVALID;
}
else if($record->E_PASSWORD!==$this->password) // here I compare db password with passwod field
{ $this->_id=$this->username;
$this->errorCode=self::ERROR_PASSWORD_INVALID;
}
else
{
$this->_id=$record['VarUser_type'];
$this->setState('title', $record['VarUser_type']);
$this->errorCode=self::ERROR_NONE;
}
return !$this->errorCode;
}