迭代多维JSONObject并获取内部对象的特定值

Question

我希望你能帮助我解决让我发疯的事情

我在这里有这个简单的Json：

    {"2":{"picture":"0","id":52,"bought_date":"2014-08-01","mileage":0,"bike_id":21861,"hours":0,"name":"YZ450F","pictures":"","year":2013,"user_id":34,"cost":8000},"1":{"picture":"140","id":51,"bought_date":"2014-07-28","mileage":0,"bike_id":21130,"hours":0,"name":"Yamaha WR450F 2013","pictures":"","year":2013,"user_id":34,"cost":0},"0":{"picture":"0","id":53,"bought_date":"2014-08-01","mileage":0,"bike_id":18310,"hours":0,"name":"MX 300","pictures":"","year":2011,"user_id":34,"cost":0}}

我将此JSONObject发送到Display_Bikes（），它应该迭代JSONObject的每个元素，然后选择每个id值以触发另一个方法

在伪代码中它看起来像这样

foreach Json as bike{

    get bike.id then
        call anothermethod(bike.id)

}

在现实中，我不知道我做错了什么，这是我第四天使用Java，所以这是可以理解的，但我真的很沮丧

这是我正在研究的幼稚方法，非常感谢任何帮助：

public static void Display_Bikes(JSONObject Bikes){
    Log.v("Bikes", Bikes.toString());
    Iterator<String> iter = Bikes.keys();
    while (iter.hasNext()) {
        String key = iter.next();
        try {
            Object Bike = Bikes.get(key).toString();
            Log.v("Bike", Bike.toString());
            //Now, how to get Bike.id?
        }
        catch(JSONException e){
            //error
        }
    }
}

Answer 1

您可以使用getJSONObject(String key)获取内部对象：

while (iter.hasNext()) {
    String key = iter.next();
    try {
        JSONObject bike = Bikes.getJSONObject(key);
        Log.v("Bike", bike.toString());
        int id = bike.getInt("id");
    } catch(JSONException e) {}

}