Question

这是一个愚蠢的问题，但我似乎无法找到答案。

我有一个foreach循环，可以找到特定链接上的所有图像。我想编码所有这些图像，然后将它们写入数据库。如果我将sql查询放在foreach循环中，那么为每个图像创建一个新行，如果我将sql查询放在foreach循环之外，则只写入第一个图像。如果我尝试分别编写图像和其余数据，插入会将$ newimage视为null并覆盖值。任何建议都会受到赞赏吗？

foreach($html->find('img') as $images) {
$newimage = json_encode($images->src);
echo $newimage;
}


$sql="INSERT INTO data (headline, images, email, date, category, area, number,   crawled, lastcrawled, description)
VALUES ('$headline', '$newimage', '$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";

Answer 1

希望这会对你有所帮助。

$newimages = array();
foreach($html->find('img') as $images) {
 $newimages[] = $images->src;
}

$newimage = json_encode($newimages);

相同的sql然后 -

$sql="INSERT INTO data (headline, images, email, date, category, area, number,   
crawled, lastcrawled, description) VALUES ('$headline', '$newimage',    
$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";

Answer 2

根据您的评论，这应该可以为您提供所需的内容：

// create an array to hold the image sources
$store_images = array();
foreach($html->find('img') as $images) {
    // add the image sources to the array
    $store_images[] = $images->src;
}

// encode the entire array of images
$json_store_images = json_encode($store_images);

// store the encoded images along with the other data
$sql="INSERT INTO data (headline, images, email, date, category, area, number,   crawled, lastcrawled, description)
VALUES ('$headline', '$json_store_images', '$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";

将ForEach循环写入数据库

2 个答案: