使用正则表达式拆分表达式

Question

regexp(l,'(\W*+\d{1,3}:\d{1,2})','split')

您好， 这是我的reg exp代码。 这是我的输出

46:28 Corner, Switzerland. Conceded by Walter Ayoví. 46:26 Attempt blocked. Stephan Lichtsteiner (Switzerland) left footed shot from outside the box is blocked. Assisted by Granit Xhaka. 45:00][Second Half begins Switzerland 0, Ecuador 1. 45:00 Substitution]

我想添加量词分割

46:28 Corner, Switzerland. Conceded by Walter Ayoví. 
46:26 Attempt blocked. Stephan Lichtsteiner (Switzerland) left footed shot from outside the box is blocked. Assisted by Granit Xhaka. 
45:00][Second Half begins Switzerland 0, Ecuador 1. 
45:00 Substitution]

接收此类输出

如何在此代码中添加拆分量词，以便在遇到时间字符串（##:##）时从新行开始。

Answer 1

我不确定你要分裂的是什么，但这里sed：

sed -r s/([0-9][0-9]:[0-9][0-9])/\n\1/g

请注意，这会在第一行之前添加换行符。