Question

我有一个SQL语句（MS SQL Server 2005），可以简单计算几条记录中日期的差异。我也希望返回DATEDIFFs的总数/总和。

SELECT     (DATEDIFF(day, StartDate, EndDate)+1) AS myTotal
FROM         myTable
WHERE     (Reason = '77000005471247')

如何从myTotal获取SUM？这就是我想要回归的全部。

提前致谢

Answer 1

如果包含任何其他列，则还需要包含GROUP BY子句

SELECT     AnotherColumn, SUM(DATEDIFF(day, StartDate, EndDate)+1) AS myTotal
FROM         myTable
WHERE      (Reason = '77000005471247')
GROUP BY   AnotherColumn

Answer 2

使用SUM聚合：

SELECT     SUM(DATEDIFF(day, StartDate, EndDate)+1) AS myTotal
FROM         myTable
WHERE     (Reason = '77000005471247')

获得约会结果的总和

2 个答案: