如何通过索引分配对象数组？ （C ++）

Question

以下是我Character类的构造函数：

Character(int, int, int, string, string, string, string, string, double, double, bool, bool);

在主要功能中，这是我尝试的方式：

Character character[100];
character[0] = {777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true};
character[1] = {707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true};

错误状态，它没有存储类或类型说明符..

编辑* 最后用这个做对了： p / s - 请提供更好的解决方案。 = /

Character character[100] = { character[0] = { 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true },
                             character[1] = { 707, 5, 10, "two", "type2", "desc2", "status", "gun", 15.0, 23.4, true, true },
                             character[2] = { 888, 7, 43, "three", "type3", "desc3", "status", "sword", 15.0, 23.4, false, false } };

Answer 1

假设您已正确定义operator=，您可以执行以下操作：

Character character[100];
character[0] = Character( 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true );
character[1] = Character( 707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true );

Answer 2

如果你只想有选择地初始化数组中的元素，C99有designated initializers，它似乎也适用于C ++。

Character character[100] = {
    [0] = Character( 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true ),
    [1] = Character( 707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true )
};

您还必须为其余元素设置默认的Character构造函数。

然而，在C ++ 11中这个功能seems to not exist但gcc似乎可以处理它（可能通过扩展）。