Question

我正在编写一个程序，其中我使用倒计时直到特定的日期和时间，结果我得到 倒计时的小时，分钟，秒格式< / em> ，但我也想显示天数

获得这个：

Time remaining: 630 hours, 57 minutes, 25 seconds

需要这个：

Time remaining: 26 days, 11 hours, 57 minutes, 25 seconds

活动代码： -

public void onTick(long millisUntilFinished) { String result = ToReadableString(new org.joda.time.Period(millisUntilFinished)); countdown.setText("Time remaining: " + result); } private String ToReadableString(Period period) { int days = period.get(DurationFieldType.days()); int hours = period.get(DurationFieldType.hours()); int minutes = period.getMinutes(); int seconds = period.getSeconds(); StringBuilder sb = new StringBuilder(); if (days > 0) { sb.append(days); if (days == 1) { sb.append(" day, "); } else { sb.append(" days, "); } } if (hours > 0) { sb.append(hours); if (hours == 1) { sb.append(" hour, "); } else { sb.append(" hours, "); } } if (minutes > 0) { sb.append(minutes); if (minutes == 1) { sb.append(" minute, "); } else { sb.append(" minutes, "); } } if (seconds > 0) { sb.append(seconds); if (seconds == 1) { sb.append(" second, "); } else { sb.append(" seconds, "); } } String result = sb.toString().trim(); if (result.endsWith(",")) result = result.substring(0, result.length() - 1); return result; } }

Answer 1

编辑：

我正在编辑这个以强调为什么让Jodatime做重物可能是一个更好的选择。你可以完全删除ToReadableString，你需要的只是（我将一些变量拉到常量中，这不是绝对必要的）：

private static final PeriodType PERIOD_TYPE = PeriodType.dayTime().withMillisRemoved();
private static final PeriodFormatter PERIOD_FORMATTER = PeriodFormat.getDefault();

public void onTick(long millisUntilFinished) {
    Period period = new Period(millisUntilFinished, PERIOD_TYPE);
    countdown.setText("Time remaining: " + PERIOD_FORMATTER.print(period));
}

在最上面，你可以轻松获得Jodatime的所有好处。更少的代码，更少的错误。

编辑结束;

Joda时间的public Period(long duration)构造函数使用标准字段集，因此不包括年/日等，您应该使用替代构造函数public Period(long duration, PeriodType type)

为您的示例替换：

String result = ToReadableString(new org.joda.time.Period(millisUntilFinished));

使用：

String result = ToReadableString(new org.joda.time.Period(millisUntilFinished, org.joda.time.PeriodType.dayTime().withMillisRemoved()));

作为旁注，Jodatime可以将痛苦从一段时间转换为字符串。请使用PeriodFormatter。 e.g：

String yourOutputString = PeriodFormat.getDefault().print(period);

您可能希望修复导入以提高可读性。

Fyr：Joda time Javadoc

Answer 2

在ToReadableString函数中，只需执行以下操作即可获得从小时开始的天数 - 您还必须解决其他差异：

int days = hours/24;
hours = hours % 24;


//rest of conversion code

Answer 3

您可以手动计算。我在下面粘贴方法，用于从MilliSecond的差值计算小时和秒的日期。

public static String getDateHourMinSecond(long diffMillis) {

    long days = TimeUnit.MILLISECONDS.toDays(diffMillis);
    diffMillis -= TimeUnit.DAYS.toMillis(days);
    long hours = TimeUnit.MILLISECONDS.toHours(diffMillis);
    diffMillis -= TimeUnit.HOURS.toMillis(hours);
    long minutes = TimeUnit.MILLISECONDS.toMinutes(diffMillis);
    diffMillis -= TimeUnit.MINUTES.toMillis(minutes);
    long seconds = TimeUnit.MILLISECONDS.toSeconds(diffMillis);
    String dhms = days + " : " + hours + " : " + minutes + " : " + seconds;
    return dhms;
}

Answer 4

尝试此功能

public void clockCounter(Date startTime) {
Date currentDate =null;
SimpleDateFormat dateFormat = new SimpleDateFormat(
                    "yyyy-MM-dd HH:mm:ss");

            Calendar cal = Calendar.getInstance();
            currentDate = dateFormat.parse(dateFormat.format(cal.getTime()));

        long diffInSec = startTime.getTime() - currentDate.getTime();

        long seconds = diffInSec % 60;
        diffInSec /= 60;
        long minutes = diffInSec % 60;
        diffInSec /= 60;
        long hours = diffInSec % 24;
        diffInSec /= 24;
        long days = diffInSec;

        Log.i("Difference", days+":"+hours+":"+minutes+":"+seconds);
    }

CountDown计时器未显示剩余天数

4 个答案: