Question

//program to display message using function as a parameter
#include<stdio.h>
#include<process.h>
//return name
char name_display(char *name)
{
    return *name;
}
//display name
void display(char (*display)(char *name1),char *name2)
{
    char name3;
    name3=display(name2);
    printf("name is %s",name3);
}
void main()
{
    display(name_display,"message");
}

Answer 1

当然：printf("name is %s",name3);想打印一个字符串，但name3只是char。要么修复它：

printf("name is %c",name3);

或将您的代码修改为：

char* name_display(char *name)
{
    return name;
}
//display name
void display(char* (*display)(char *name1),char *name2)
{
    char* name3;

ie：使用字符串而不是字符。

Answer 2

尝试以下更改 - （查看程序中的修复程序）

#include<stdio.h>
#include<string.h>
//return name
char* name_display(char *name) // Fix 1, when you are returning char array use char *
{
    return name; // Fix 2 (return only the name of the array, no need of *name)
}
//display name
void display(char* (*display_call)(char *name1),char *name2) // Don't use same Function name. When you look at the program again it may confuse you
{
    char *name3; // Fix 3 
    name3 = display_call(name2);
    printf("name is %s \n",name3);
}
void main()
{
    display(name_display,"message");
}

它无法显示消息

2 个答案: