Jquery qtip ajax问题

时间:2010-03-24 12:18:49

标签: php jquery ajax post get

我正在尝试将输入框的值(在本例中为imdb链接)发布到我的imdbgrabber.php页面,并让它将该影片的信息返回到qtip框中。

编辑:查看此处http://movieo.no-ip.org/将鼠标悬停在图片上,您会看到错误。

一切正常,直到我尝试将变量发布到imdbgrabber页面。这是代码。

使用Javascript:

 var link = $("#link").val();
    var imdbLink = 'link='+ link;

$(".moviebox").qtip({
   style: { name: 'cream' },
   content: {
     method: 'GET',
     data: imdbLink,
     url: '/includes/imdbgrabber.php',
     text: '<img class="throbber" src="/images/loading.gif" alt="Loading..." />'
   },
   position: {
         corner: {
           target: 'bottomright',
          tooltip: 'bottomleft'
        }
      }
});

HTML:

 <!--start moviebox-->
  <div class="moviebox">
  <a href="#">
  <img src="http://1.bp.blogspot.com/_mySxtRcQIag/S6deHcoChaI/AAAAAAAAObc/Z1Xg3aB_wkU/s200/rising_sun.jpg" />
  <form method="get" action="">
              <input type="text" name="link" id="link" style="display:none" value="http://www.imdb.com/title/tt0367882"/>
 </form>
  </a>
  </div>
  <!--end moviebox-->

最后是php:

<?php

$url=$_GET['link'];

//$url = 'http://www.imdb.com/title/tt0367882/';

//get the page content
$imdb_content = get_data($url);

//parse for product name
$name = get_match('/<title>(.*)<\/title>/isU',$imdb_content);
$director = strip_tags(get_match('/<h5[^>]*>Director:<\/h5>(.*)<\/div>/isU',$imdb_content));
$plot = get_match('/<h5[^>]*>Plot:<\/h5>(.*)<\/div>/isU',$imdb_content);
$release_date = get_match('/<h5[^>]*>Release Date:<\/h5>(.*)<\/div>/isU',$imdb_content);
$mpaa = get_match('/<a href="\/mpaa">MPAA<\/a>:<\/h5>(.*)<\/div>/isU',$imdb_content);
$run_time = get_match('/Runtime:<\/h5>(.*)<\/div>/isU',$imdb_content);
$rating = get_match('/<div class="starbar-meta">(.*)<\/div>/isU',$imdb_content);

////build content
//$content = '<h2>Film</h2><p>'.$name.'</p>'
//          . '<h2>Director</h2><p>'.$director.'</p>'
//          . '<h2>Plot</h2><p>'.substr($plot,0,strpos($plot,'<a')).'</p>'
//          . '<h2>Release Date</h2><p>'.substr($release_date,0,strpos($release_date,'<a')).'</p>'
//          . '<h2>MPAA</h2><p>'.$mpaa.'</p>'
//          . '<h2>Run Time</h2><p>'.$run_time.'</p>'
//          . '<h2>Full Details</h2><p><a href="'.$url.'" rel="nofollow">'.$url.'</a></p>';



//gets the match content
function get_match($regex,$content)
{
    preg_match($regex,$content,$matches);
    return $matches[1];
}

//gets the data from a URL
function get_data($url)
{
    $ch = curl_init();
    $timeout = 5;
    curl_setopt($ch,CURLOPT_URL,$url);
    curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
    curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
    $data = curl_exec($ch);
    curl_close($ch);
    return $data;
}
?>

  <!--start infobox-->
    <div class="info"> 
  <span>
  <?php echo '<strong>'.$name.'</strong>' ?>
  </span>

  <img src="http://1.bp.blogspot.com/_mySxtRcQIag/S6deHcoChaI/AAAAAAAAObc/Z1Xg3aB_wkU/s200/rising_sun.jpg" /> 
  <div class="plot">
  <?php echo ''.substr($plot,0,strpos($plot,'<a')).'</div>' ?>
  </div>

  <div class="runtime">
  <?php echo'<strong>Run Time</strong><br />'.$run_time.'</div>' ?>
  </div>
<div class="releasedate">
<?php echo '<strong>Release Date</strong><br />'.substr($release_date,0,strpos($release_date,'<a')).'</div>' ?>
</div>
<div class="director">
<?php echo '<strong>Director</strong><br />'.$director.'' ?>
</div>
  <div class="rating">
  <?php echo '<strong>Rating</strong><br />'.$rating.'' ?>
  </div>
  </div>
  <!--end infobox-->

我确信这是一个简单的错误,但看了几个小时后,我想我会问专家。

1 个答案:

答案 0 :(得分:1)

根据文档,通过AJAX获取时qtip的数据需要是键值对。试试这个:

var link = $("#link").val();
var imdbLink =  { "link" : link };  // note change to data...

$(".moviebox").qtip({
   style: { name: 'cream' },
   content: {
     method: 'GET',
     data: imdbLink,   // you could make this { "link" : link }
     url: '/includes/imdbgrabber.php',
     text: '<img class="throbber" src="/images/loading.gif" alt="Loading..." />'
   },
   position: {
         corner: {
           target: 'bottomright',
          tooltip: 'bottomleft'
        }
      }
});

此外,您的get_match例程似乎不正确地索引到matches数组中。数组是从零开始的,因此第一个匹配是索引0处的匹配,而不是一个匹配。实际上,由于您只有一个分组表达式,因此您只能使用正则表达式进行单个匹配。

尝试将其更改为:

//gets the match content  
function get_match($regex,$content)  
{  
    preg_match($regex,$content,$matches);  
    return $matches[0];
}