Question

我对这些问题的措辞很可怕，但我希望能够对我正在尝试做的事情有充分的了解。

我有7页和7张图片，图片全部是“waterfall_01.jpg”，“waterfall_02.jpg”等，最多7张。

到目前为止，我的代码很简单：

    <?php 
        $cp = basename($_SERVER['PHP_SELF']);
        $cf = dirname($_SERVER['PHP_SELF']);
    ?>
    <img src="/img/waterfall_0<?php if ($cp == "about.php" || $cf == "/about"){ echo "1"; }?>.jpg" />

如何根据7个不同的页面更改此代码以回显介于1和7之间的不同数字（其中一些页面的文件夹下方有一些文件夹在下拉菜单中显示）。

从技术上讲，我可以写一个非常长的行：

    <img src="/img/waterfall_0<?php
        if ($cp == "home.php"){ echo "1"; }
        if ($cp == "about.php" || $cf == "/about"){ echo "2"; }
        if ($cp == "products.php" || $cf == "/products"){ echo "3"; }
        if ($cp == "services.php" || $cf == "/services"){ echo "4"; }
        if ($cp == "gallery.php" || $cf == "/gallery"){ echo "5"; }
        if ($cp == "faq.php"){ echo "6"; }
        if ($cp == "contact.php"){ echo "7"; }
    ?>.jpg" />

我对PHP不是那么好，我不确定上述是否是最佳或正确的方式，所以所有的帮助都表示赞赏！

测试服务器为http://www.mrobertsdesign.ca/home.php

提前致谢！

Answer 1

<?php

$requestedURI = $_SERVER['REQUEST_URI'];

$images = array(
    "/home" => "1",
    "/about" => "2",
    "/products" => "3",
    "/services" => "4",
    "/gallery" => "5",
    "/faq" => "6",
    "/contact" => "7",
);

?>

<img src="/img/waterfall_0<?= $images[$requestedURI]; ?>.jpg"/>

只需确保您的网址与数组密钥匹配。

Answer 2

Justin Workman和Satish Sharma的两个答案都是可行的解决方案。但为什么不通过另一种选择。切换语句。

$url = $_SERVER['REQUEST_URI'];
switch ($url) {
    case '/about':
    case '/about.php':
        $img = 2;
        break;
    case '/contact':
    case '/contact.php':
        $img = 3;
        break;
    ......
    default:
        $img = '1';
}

然后将变量输出到img标签中。

Answer 3

你需要使用if else

<?php
$cp = basename($_SERVER['PHP_SELF']);
$cf = dirname($_SERVER['PHP_SELF']);

if($cp == "home.php")
{
    $img_src = "1.jpg";
}
else if($cp == "about.php" || $cf == "/about"))
{
    $img_src = "2.jpg";
}
else if($cp == "products.php" || $cf == "/products")
{
    $img_src = "3.jpg";
}
else if($cp == "services.php" || $cf == "/services")
{
    $img_src = "4.jpg";
}
else if($cp == "gallery.php" || $cf == "/gallery")
{
    $img_src = "5.jpg";
}
else if($cp == "faq.php")
{
    $img_src = "6.jpg";
}
else if($cp == "contact.php")
{
    $img_src = "7.jpg";
}
?>
<img src="/img/waterfall_0<?php echo $img_src;?>" />

PHP：根据加载的页面更改div中的图像？

3 个答案: