Question

我的代码不起作用，我无法弄清楚原因

public function fetch_active_table_data(){
        $query = "SELECT id, name, location, admission, drink_prices, Performer FROM drinkdeals WHERE admission IS NULL";
        $stmt = $this->dbh->prepare($query);
        $stmt->execute(array("0"));

我试图只显示录取为空的事件。我究竟做错了什么？谢谢，基兰编辑：当我删除WHERE admission IS NULL时它确实有用，所以我知道问题出在哪里。感谢

Answer 1

这取决于您如何设置值。也许你应该尝试寻找一个空值，如：

public function fetch_active_table_data(){
    $query = "SELECT id, name, location, admission, drink_prices, Performer FROM drinkdeals WHERE admission=''";
    $stmt = $this->dbh->prepare($query);
    $stmt->execute(array("0"));
}

如何只在PHP表中显示列为NULL的值？

1 个答案: