Question

这里我有一个我为了通过串口发送文本文件和图像而创建的类：

 public class SendItem
{
    private byte[] bytes;
    private string _fileName;
    private string _extension;
    private int bytesSin;

    public string Extension
    {
        get { return _extension; }
        set { _extension = value; }
    }

    public string FileName
    {
        get { return _fileName; }
        set { _fileName = value; }
    }

    public byte[] Bytes
    {
        get { return bytes; }
        set { bytes = value; }
    }

    public SendItem()
    {


    }

    public void SendFile(SerialPort serialPort1)
    {
        if (serialPort1.IsOpen)
        {
            OpenFileDialog OFDialog = new OpenFileDialog();
            OFDialog.Title = "Open File";
            OFDialog.Filter = "Text Files (*.txt)" + "|*.txt|All files (*.*)|*.*";
            OFDialog.InitialDirectory = @"C:\";

            bool? userClickedOK = OFDialog.ShowDialog();

            if (userClickedOK == true)
            {
                serialPort1.DiscardInBuffer();
                string chosenFile = OFDialog.FileName;
                string ext = Path.GetExtension(OFDialog.FileName);
                _extension = ext;

                byte[] data = File.ReadAllBytes(chosenFile);
                SendItem newSendItem = new SendItem();
                newSendItem._extension = ext;
                newSendItem._fileName = System.IO.Path.GetFileNameWithoutExtension(chosenFile);
                newSendItem.bytes = data;
                byte[] view = newSendItem.Serialize();
                string test = Convert.ToBase64String(data);
                serialPort1.Write(newSendItem.Serialize(), 0, newSendItem.Serialize().Length);
                //serialPort1.Write(data, 0, data.Length);
            }
        }
    }


    public override string ToString()
    {
        return string.Format("File: {0}{1}",_fileName, _extension);
    }
}

SendFile方法中存在相当多的冗余，但我要求它会被忽略，以支持我继续使用的以下问题。

每当我从文本框发送文本文件或纯文本聊天文本时，都会执行以下代码块而不会触发捕获：

void _sPort_DataReceived(object sender, SerialDataReceivedEventArgs e)
    {
        SerialPort sp = (SerialPort)sender;

        byte[] data = new byte[sp.BytesToRead];
        string message = string.Empty;

        sp.Read(data, 0, data.Length);
        try
        {
            SendItem receivedObject = data.Deserialize<SendItem>();
            File.WriteAllBytes(@"d:\" + receivedObject.FileName + receivedObject.Extension, receivedObject.Bytes);
            message = "File has been recieved.";
            sp.Write("File sent.");
        }
        catch (Exception exp)
        {
            errors = exp.Message;
            message = Encoding.UTF8.GetString(data);
        }
        App.Current.Dispatcher.Invoke(new Action(() => _response.Add("Friend: " + message)));
    }

当我尝试发送图像时出现问题...它触发catch并提供异常XML文档中存在错误（5,3870）。

我写的序列化器和解串器如下：

public static byte[] Serialize<T>(this T source)
    {
        XmlSerializer serializer = new XmlSerializer(typeof(T));
        MemoryStream stream = new MemoryStream();
        serializer.Serialize(stream, source);
        byte[] buffer = stream.GetBuffer();
        stream.Close();
        return buffer;
    }

    public static T Deserialize<T>(this byte[] source)
    {
        XmlSerializer serializer = new XmlSerializer(typeof(T));
        MemoryStream stream = new MemoryStream(source);
        T result = (T)serializer.Deserialize(stream);
        stream.Close();
        return result;
    }

有谁可以指出我犯错误的地方？我已经调试了很多年了，我无法绕过它。

**编辑：我还包括我试图发送的图像的序列化数据，看了之后，看来我的字节对于串口来说可能太大了 - 有没有办法调整这个或允许串口取所有的发送的数据？

/ 9J / 4AAQSkZJRgABAgAAAQABAAD // gAEKgD / 4gIcSUNDX1BST0ZJTEUAAQEAAAIMbGNtcwIQAABtbnRyUkdCIFhZWiAH3AABABkAAwApADlhY3NwQVBQTAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA9tYAAQAAAADTLWxjbXMAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAApkZXNjAAAA / AAAAF5jcHJ0AAABXAAAAAt3dHB0AAABaAAAABRia3B0AAABfAAAABRyWFlaAAABkAAAABRnWFlaAAABpAAAABRiWFlaAAABuAAAABRyVFJDAAABzAAAAEBnVFJDAAABzAAAAEBiVFJDAAABzAAAAEBkZXNjAAAAAAAAAANjMgAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAB0ZXh0AAAAAEZCAABYWVogAAAAAAAA9tYAAQAAAADTLVhZWiAAAAAAAAADFgAAAzMAAAKkWFlaIAAAAAAAAG + iAAA49QAAA5BYWVogAAAAAAAAYpkAALeFAAAY2lhZWiAAAAAAAAAkoAAAD4QAALbPY3VydgAAAAAAAAAaAAAAywHJA2MFkghrC / YQPxVRGzQh8SmQMhg7kkYFUXdd7WtwegWJsZp8rGm / fdPD6TD //// bAEMACAYGBwYFCAcHBwkJCAoMFA0MCwsMGRITDxQdGh8eHRocHCAkLicgIiwjHBwoNyksMDE0NDQfJzk9ODI8LjM0Mv / bAEMBCQkJDAsMGA0NGDIhHCEyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMv / CABEIAjoCOgMAIgABEQECEQH / xAAbAAEBAAMBAQEAAAAAAAAAAAAAA QIDBAUGB // EABgBAQEBAQEAAAAAAAAAAAAAAAABAgME / 8QAGAEBAQEBAQAAAAAAAAAAAAAAAAECAwT / 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 + hTXUFBBqXbJVAAFkcnX5aaPqPzb6xx + hHXmAAAAAsqBBFtSoEAQFQSVKAAAsFAFASXCMdWeGbiM3T5 / f5zp6iXXQhalGGYwti0AJRDxvZ8evj / rfmvvLy9Uu + MAAAAAsFSpFAQABFEBIS0AACWGQAoIxwzwjXjnM3Wzi8vn + j5s36qXXaBQARKUCxZAR5Hr + Rb8z97 + dfaOX0Vl6cIFAAAAFJYKgqVAgACKMFSkoAAlFY5AAgxsjGZM3GWry8ffxze + VrtFEUQAAKsJUsPI9fy Q + M + N + X9jXL9CuOV4wUAAAAsAAoEgAAAGFiWygAACZQVKiCyWZRZLFGnk7edrC + X8w9H3j852an6C + bxxr6afN7D6B4 / bHW59yZTDmOp4 / CfTeT43RqeN6HD6u8febIvAKAAAAAFJZUCAAACDES2WFSgBKTLGiwCRFkosQpjMh8l4H0fDn0 / Nehwe50xz6PT0Z6eZr9nk1Nfs + NlNfT7vM7OTHwXL1mjX27948 / 0MfRjwvrPkfv5n3BriVZAopAAALKkpAAAAEpbgmWUAsoShKSwUCURUSgBKHF5nv + Hy6的/ F +3瓦特+ trpweZ9pyx4XF9bq1n5 + / RbJt2bts5 / B8f0fJvp8 / 2eznceL7k7sX5L9J + C + 4Z7S9eIJBVEQWikUkpAAABKSyhLWBM2gqQqwFIUAFIUlKlIgp819L5kvz / bo18fV9Ew3Xj5 + v15XH0Z60zz15acpv5a8nm + hmnmb + njy8P6bxPct9Kx6PPRAAEVQQIVKCCygEUAEpgJZYKAAlAGWNRZQQotIAGrdjHy / nbuPn6Po + 3wfWznuapvKcvTm7ctDU16tnPjXo3h3pPJ6PFuur2 /升/ oNZ + hS9OQiZQKgqCoKgWBYFgBbAsEEXEQAAqFAAsFCCkFoAhRJ8x4 / 1PhcvRwe38t6ur9BePt5TL436PwOl6NXlYbdnofP91n2nPz3heLyenye09z6j5j62Y9Ea5CqS2BKFBAAUAAEBQAGsQBUoBUFAlJUW2xIKQKFAeV819P8xz6 + P0XRrfqavKwj3 / P5s16NGVrg6ZLnq2ePnG7Vs3Wer9V8P9VMe + S81lWwAFgsCoAKgAVCoFlGNGCBUFCoKBZUJVlxyqyyS2AAS2zHwo2eBhw57dnldXntze26x6no + dv5dO3R5c1OzkVfJ5O + dOfN382s + GY + U9LOf0vo / PPeZ + lcnXcyiRYqwVAoERUFgWBYtEsEprS0lhklJQURcaoIsoBUhlNfkL7Pk / O + a37Pl + RorbpNT03H6 OOurZr0ntbfIyzeycuxNuGnVb06efOzPy / S8vWIjWM + vip7 / P / H7M39E9n8v2n6i + H + nmfQVElARKhYogLIZSoJSVKxhVgVKLBbCAUEqkmOlc / H5vkl9jg8vVddPNi1KhAq9vBsl9HCY56btGrXZumqp046Kt36tKXQXIWAluI2Z6Kd3b42Uv6F9L + Rfex78yxzEWICZYiglgsQyRFxyhjY1FlIFoSgASwyjUuHF1eFm / OeRnp60hFkMoVUAhlt57L0YMJWWpZta8TdqgCxYMmNBEqFyuNTPs4afrXd + cfpGWMymEBLAIVKEsCFxzxIl1CVQRYKsKgWBo26Jdfyn0 / wU35WNx65rEqwlSgUlglRACAFRVQUIAQWC241Llhkuz9M / MPpJP0WZY4QkkosWAFxsKiLAljUmWNWpUJRZQlBDHRt0y8H579j8RrWvG46lsFbequF62B5j07J5c9XBfOnpLPMdkOSdkl5Has4naOK9mRwvTHmPR1HE3ajELYiZZYZLl08mcfs2Xk + rmJZmLiWy4lISkACmA1FgtgJS3FbbBYkmrTt5835D5j0 / L6akssAZY09PzeziKQuWHZW3i2c6d / B18q4ki9nF6Fmvk2aoZY1ero4MU9rW85NunVLUsUItgyywyPvvrPhfusyQzIUhFWUkIygEyNdjapZFgoJlFLLCIujl6vOy / POXPX1ogsKybE6eTfsrlwysYbcZXZwdNTPi261xlRM8Ok6fP6uUgq3HI9LzvT8xJjYSEtsFSlyxp9T + hfm36RmSS5kuIyiKsCWCxFiBLsssgAluSCkkyxsOfwvc + czfhpZ1qCiGzZpqdDRsrPbpyM7q3

Answer 1

它可能是也可能不是整个问题，但这肯定是问题：

byte[] buffer = stream.GetBuffer();

这很可能会返回比你想要的更多的数据 - 因为它并不局限于流的长度。 MemoryStream有一个方便的MemoryStream.ToArray方法来简化：

public static byte[] Serialize<T>(this T source)
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));
    MemoryStream stream = new MemoryStream();
    serializer.Serialize(stream, source);
    return stream.ToArray();
}

（关闭您创建的MemoryStream没有任何好处 - 如果认为您需要，则应使用using语句。）

同样，您的Deserialize方法可以简化为：

public static T Deserialize<T>(this byte[] source)
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));
    return (T) serializer.Deserialize(new MemoryStream(source));
}

鉴于您有效地尝试反序列化“XML文档 - 然后可能是一堆”空白“数据，这可能就是问题。

编辑：现在还有第二个问题：

byte[] data = new byte[sp.BytesToRead];
string message = string.Empty;

sp.Read(data, 0, data.Length);

您假设所有数据都可以一次性读取。如果数据多于串行端口的缓冲区大小，则情况并非如此。相反，如果你试图将多个“消息”放到有效的流上，你需要指示消息的结束（并在你找到之前继续阅读）或写消息本身之前的消息长度 - 然后在读取时读取该长度，然后确保读取那么多字节。

当您尝试将面向流的协议用作面向消息的协议时，这是一个标准问题。

Answer 2

您应该使用ToByteArray()代替GetBuffer()。

串行端口 - XML文档中存在错误（5,3870）

2 个答案: