Question

我试图将表单操作重定向到另一个页面，但是，我对Django框架并不太熟悉。我参加了民意调查教程。

我项目中的当前urls.py是：

from django.conf.urls import patterns, include, url
from django.contrib import admin
from WebApp import views
from StripCal import views
admin.autodiscover()

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
    url(r'^webapp/', include('WebApp.urls', namespace="WebApp")),
    url(r'^stripcal/', include('StripCal.urls', namespace="StripCal")),
)

The url.py in my stripcal app is:

from django.conf.urls import patterns, include, url
from django.contrib import admin
from StripCal import views

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^run', views.detail, name='detail'),
)

当我输入

时

http://127.0.0.1:8000/stripcal/
http://127.0.0.1:8000/webapp/

它成功转到两个不同的应用程序。但是，我不太熟悉{％url＆＃39; app_name：view_name＆＃39; ％} 句法。好像＆＃39; app_name：view_name＆＃39;成为/ app_name / view_name

这是我目前的观点：

from django.shortcuts import get_object_or_404, render
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse
from django.views import generic

# Create your views here.

def index(request):
    context = {'somethingDownByCelery': "heh"}
    return render(request, 'StripCal/index.html', context)

def detail(request):
    context = {'somethingDownByCelery': "heh"}
    return render(request, 'StripCal/detail.html', context)

我的Index.html

{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'StripCal/index.css' %}"/>

<form action="{% url 'stripcal:detail'%}" method="post">
    {% csrf_token %}
    <p> StripCal Input </p>
    <textarea name="StripCal_Input" cols="30" rows="10"> </textarea>
    <br> <br>
    <input type="submit" value="Submit">
</form>

我的Detail.html

{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'StripCal/detail.css' %}"/>

Hello Detail!

当我删除操作= {％url＆＃39; stripcal：detail＆＃39; ％}网页加载，但是，当我把它放入，页面甚至没有加载（HTTP 500）。

Answer 1

尝试改变： StripCal.url.py

urlpatterns = patterns('StripCal.views',
url(r'^$', 'index', name='index'),
url(r'^run','detail', name='detail'),

）

Django - 项目中的urls.py和app中的url.py

1 个答案: