Question

问题在于......我需要使用＃34;％＆＃34;等特殊字符组合一些NSStrings。或＆＃34;＆amp;＆＃34;。现在，即使是＆＃34;％＆＃34;根本不显示：

-(void)getPostingURL:(NSString*)path variablesNames:(NSArray*)names{
    NSString *result = path;
    for (int i=0; i<names.count; i++){
        result = [NSString stringWithFormat:@"%@?%@=&@&",result,names[i]];
    }
    NSLog(result);
}

这是我想得到的结果：调用

[self getPostingURL:@"http://www.myurl.com/middleInteractionPost.php" variablesNames:@[@"name",@"state",@"language"]];

最终字符串

http://www.myurl.com/middleInteractionPost.php?name=%@&state=%@&language=%@

Answer 1

百分号的转义码为“%%”，因此您的代码应替换为“%%”，并显示“％”。

Answer 2

使用此代码：

-(void)getPostingURL:(NSString*)path variablesNames:(NSArray *)names
{
    NSString *result = path;
    result = [result stringByAppendingString:@"?"];
    for (NSString *variableName in names){
       NSString *stringToAppend = [NSString stringWithFormat:@"%@=%%@", variableName];
       result = [result stringByAppendingString:stringToAppend];

       if (![variableName isEqual:[names lastObject]]) {
           result = [result stringByAppendingString:@"&"];
       }
    }
    NSLog(@"%@", result);
}

它将构造并打印此字符串：

http://www.myurl.com/middleInteractionPost.php?name=%@&state=%@&language=%@

写'＃34;特殊字符＆＃34;例如＆＃34;％＆＃34;在Objective-C中

2 个答案: