Question

我正在使用文件上传器并需要请求有效负载中的详细信息来裁剪它。

func Upload(w http.ResponseWriter, r *http.Request) {
    reader, err := r.MultipartReader()
    if err != nil {
        http.Error(w, err.Error(), http.StatusInternalServerError)
        return
    }
    //copy each part to destination.
    for {
        part, err := reader.NextPart()
        if err == io.EOF {
            break
        }
        if part.FormName() == "avatar_data"{
           // Read the content in "avatar_data" how?
        }
        if part.FileName() == "" {
            continue
        }
        dst, err := os.Create("/Users/macadmin/test/" + part.FileName())
        defer dst.Close()
        if err != nil {
            http.Error(w, err.Error(), http.StatusInternalServerError)
            return
        }
        if _, err := io.Copy(dst, part); err != nil {

            http.Error(w, err.Error(), http.StatusInternalServerError)
            return
        }
    }
    img, _ := imaging.Open("/Users/macadmin/test/cry3.jpg")
    if err != nil {
        panic(err)
    }

    rect := image.Rect(0, 0, 200, 500)
    // rect := image.Rectangle{20,20}
    dst := imaging.Crop(img, rect)
    err = imaging.Save(dst, "/Users/macadmin/test/cry4.jpg")
    if err != nil {
        panic(err)
    }
    //display success message.
}

我没有10个代表来发布POST请求的图像，但它有

Content-Disposition: form-data; name="avatar_data"

{"x":528,"y":108,"height":864,"width":864}

因此，从avatar_data我需要x，y，height和width。我知道我必须整理JSON，但我不确定如何达到这一点？

Answer 1

multipart.Part实现了io.Reader接口。

if part.FormName() == "avatar_data" {
    j, err := ioutil.ReadAll(part)
    if err != nil {
        //do something
    }
    //j == []byte(`{"x":528,"y":108,"height":864,"width":864}`), do something with it.
}

在Go中读取请求有效负载？

1 个答案: