我正在我的页面中进行分页,但我收到这样的错误。
遇到PHP错误
严重性:注意
消息:未定义的属性:Home :: $ login_model
文件名:controllers / home.php
行号:41
致命错误:在非对象中调用成员函数getDet() C:\ XAMPP \ htdocs中\毕加索\ new_design \ photo_frame \应用\控制器\ home.php 在第41行
这是我的代码
型号:
function getDet(){
$query_str = "SELECT * FROM frame";
$result = $this->db->query($query_str);
return $result;
}
控制器:
public function frame1()
{
$things = $this->login_model->getDet();
$total_rows = $things->num_rows();
$this->load->library('pagination');
$config['base_url'] = base_url() . 'home/';
$config['total_rows'] = '$total_rows';
$config['per_page'] = '1';
$this->pagination->initialize($config);
$this->view_data['pagination'] = $this->pagination->create_links();
$this->view_data['things'] = $things;
$this->load->model('login_model');
$data1['wood']=$this->login_model->getDetails('wood');
$this->load->view('frame1',$data1);
}
查看:
<div>
<?php if($wood!=""||$wood!=null){foreach($wood as $row){ ?>
<div class="frm1" style="border:1px solid rgb(204, 204, 204); background-color: rgb(244, 244, 244);list-style-type:none; float:left; display:inline; padding:20px;">
<img src="<?php echo base_url()."uploads/frame/icon/".$row['iconimage'];?>" style="cursor:pointer" class="changemount" data-id="<?php echo base_url()."uploads/frame/".$row['frameimage'];?>"
data-price="<?php echo $row['price'];?>" data-thick="<?php echo $row['thickness'];?>" data-change="0" data-w="515" data-h="356" data-ch="385" data-cw="554" /></div>
<?php }} ?>
</div>
<?php echo $pagination; ?>
</div>
答案 0 :(得分:1)
在使用之前,您必须加载模型。
public function frame1() {
$this->load->model('login_model'); //You have to load this model, before use it
$things = $this->login_model->getDet(); $total_rows = $things->num_rows();
$this->load->library('pagination');
$config['base_url'] = base_url() . 'home/';
$config['total_rows'] = '$total_rows';
$config['per_page'] = '1';
$this->pagination->initialize($config);
$this->view_data['pagination'] = $this->pagination->create_links();
$this->view_data['things'] = $things;
$data1['wood']=$this->login_model->getDetails('wood');
$this->load->view('frame1',$data1);
}
答案 1 :(得分:0)
undefined login_model,表示您在不加载模型的情况下调用模型,将其添加到控制器中的_construct
$this->load->model("model_name");
并且在您的视图中,您错过了一些重要的事情,要在循环中执行您的代码,请执行以下代码
//add the ->result() in your var $wood
foreach($wood->result() as $row)
这将解决您的错误