Question

我在Hive中运行下一个查询：

SELECT COUNT(*) 
FROM 
  (
   SELECT * 
   FROM 
   (SELECT id, COUNT(*) AS count_p_id FROM palladion GROUP BY id) a, 
   (SELECT cid, COUNT(*) AS count_q_cid FROM operations GROUP BY cid) b 
   WHERE a.id=b.cid
  ) 
WHERE count_p_id < count_q_cid;

我一直收到像

这样的错误

 ParseException line 1:103 mismatched input ',' expecting ) near 'a' in subquery source

代码有什么问题？我看不到任何。

Answer 1

从Hive 0.13.0开始支持隐式连接表示法。这允许FROM子句加入以逗号分隔的表列表，省略JOIN关键字。例如：

SELECT *
FROM table1 t1, table2 t2
WHERE t1.id = t2.id

我希望你正在使用＆lt; 0.13.0版本。如果你的hive版本是＆lt; 0.13.0

试试这个：你必须使用JOIN - ON，而不是逗号 - WHERE

SELECT COUNT(*) 
FROM 
  (
   SELECT * 
   FROM 
   (SELECT id, COUNT(*) AS count_p_id FROM palladion GROUP BY id) a JOIN 
   (SELECT cid, COUNT(*) AS count_q_cid FROM operations GROUP BY cid) b 
   ON  a.id=b.cid
  ) 
WHERE count_p_id < count_q_cid;

ParseException - 子查询源中的输入不匹配 - Hive中的错误

1 个答案: