Question

需要将固定宽度文件转换为＆＃39;逗号＆＃39;在unix中分隔。

k12582927001611USNA
k12582990001497INAS
k12583053001161LNEU

必需的输出：

k,1258292700,1611,US,NA
k,1258299000,1497,IN,AS
k,1258305300,1161,LN,EU

Answer 1

像这样：

awk -v FIELDWIDTHS="1 10 4 2 2" -v OFS=, '{print $1,$2,$3,$4,$5}' file

OFS是输出字段分隔符，我将其设置为逗号。 FIELDWIDTHS变量为您带来了所有魔力。

或者你可以在Perl这样做：

perl -ne 'm/(.)(.{10})(....)(..)(..)/; printf "%s,%s,%s,%s,%s\n",$1,$2,$3,$4,$5' file

或者，像sed这样：

sed -E 's/(.)(.{10})(....)(..)(..)/\1,\2,\3,\4,\5/' file

Answer 2

使用awk和substr()：

awk -v OFS=, '{ print substr($0, 1, 1), substr($0, 2, 10), substr($0, 12, 4), substr($0, 16, 2), substr($0, 18, 2) }' file

输出：

k,1258292700,1611,US,NA
k,1258299000,1497,IN,AS
k,1258305300,1161,LN,EU

Answer 3

您可以通过以下方式管道传输文件：

awk '{print substr($0,1,1)","substr($0,2,10)","substr($0,12,4)","substr($0,16,2)","substr($0,18,2)}'

按照以下测试运行：

pax> echo 'k12582927001611USNA
k12582990001497INAS
k12583053001161LNEU' | awk '
{
    print substr($0,1,1)","substr($0,2,10)","substr($0,12,4)","
        substr($0,16,2)","substr($0,18,2)
}'

k,1258292700,1611,US,NA
k,1258299000,1497,IN,AS
k,1258305300,1161,LN,EU

需要将固定宽度文件转换为在unix中分隔的“逗号”

3 个答案: