String语句从switch语句返回null

时间:2014-07-31 04:03:50

标签: java android string null switch-statement

我目前正在开发一款Android应用程序,可让您在VideoView中观看流媒体视频。我有一种方法允许您通过switch语句选择四个流中的一个。这是正常的,其代码如下:

public void playStream(int position) {
    switch (position) {
        case 0:
            streamOn = true;
            streamPos = 0;
            logString = "M";
            posSelected = "0";
            break;
        case 1:
            streamOn = true;
            streamPos = 1;
            logString = "J";
            posSelected = "1";
            break;
        case 2:
            streamOn = true;
            streamPos = 2;
            logString = "B";
            posSelected = "2";
            break;
        case 3:
            streamOn = true;
            streamPos = 3;
            logString = "N";
            posSelected = "3";
            break;
        default:
            break;
    }
    checkStreamLink(position);

    Log.wtf(logString, posSelected);
    Log.wtf(logString, streamURL);
}

无法正常工作的是,在这种选择流的方法中,我调用了另一个运行线程的方法(checkStreamLink();)。根据您选择的流,线程将调用另一个打开网页的方法,读取一行文本,然后将该文本设置为String streamURL。这两种方法的代码如下:

public void checkStreamLink(final int position) {
    Thread thread = new Thread(new Runnable() {
        @Override
        public void run() {
            try {
                switch (position) {
                    case 0:
                        streamURL = getStreamLink("LINK 0 GOES HERE");
                        break;
                    case 1:
                        streamURL = getStreamLink("LINK 1 GOES HERE");
                        break;
                    case 2:
                        streamURL = getStreamLink("LINK 2 GOES HERE");
                        break;
                    case 3:
                        streamURL = getStreamLink("LINK 3 GOES HERE");
                        break;
                    default:
                        break;
                }
            }
            catch (Exception e) {
                e.printStackTrace();
            }
        }
    });
    thread.start();
}


public String getStreamLink (String textSource) {
    URL streamURL;
    String errorParsingURL = "ERROR PARSING URL";
    try {
        streamURL = new URL(textSource);
        BufferedReader bufferReader = new BufferedReader(new InputStreamReader(streamURL.openStream()));
        String StringBuffer;
        String stringText = "";
        while ((StringBuffer = bufferReader.readLine()) != null) {
            stringText += StringBuffer;
        }
        bufferReader.close();
        return stringText;
    }
    catch (MalformedURLException e) {
        e.printStackTrace();
    }
    catch (IOException e) {
        e.printStackTrace();
    }
    return errorParsingURL;
}

我遇到的问题是String streamURL在首次使用时返回null,正如我所包含的Log语句所证明的那样。每次在此之后选择流时,String streamURL将返回您上次选择流时应收到的文本。我似乎无法弄清楚为什么会发生这种情况,我将不胜感激。

1 个答案:

答案 0 :(得分:1)

您将获得null,因为 getStreamLink 在您打印完结果后返回其值。在 getStreamLink 方法的末尾打印结果日志消息,以查看正在返回的实际值,并在该点调用任何其他功能。