Question

我想从XML文件中提取信息。我尝试了Mathworks中的示例，但它没有用。以下是文件中的示例信息：

<?xml version="1.0" encoding="iso-8859-1"?>
<CS-info>
<cs name="abc">
<var name="a" unit="s1"/>
<var name="b" unit="s2"/>
.
.
</cs>
.
.
.
</CS-info>

当选择“cs name”时，该节点中相应的变量名称和单位应该被提取为单元格数组。有人有解决方案吗？预期的输出是

output={'a','s1';'b','s2';...};

Answer 1

在xmlread的文档中，已经显示了几个示例函数来帮助您解析XML文档。如果代码被删除，代码将被复制如下 -

function theStruct = parseXML(filename)
% PARSEXML Convert XML file to a MATLAB structure.
try
   tree = xmlread(filename);
catch
   error('Failed to read XML file %s.',filename);
end

% Recurse over child nodes. This could run into problems 
% with very deeply nested trees.
try
   theStruct = parseChildNodes(tree);
catch
   error('Unable to parse XML file %s.',filename);
end


% ----- Local function PARSECHILDNODES -----
function children = parseChildNodes(theNode)
% Recurse over node children.
children = [];
if theNode.hasChildNodes
   childNodes = theNode.getChildNodes;
   numChildNodes = childNodes.getLength;
   allocCell = cell(1, numChildNodes);

   children = struct(             ...
      'Name', allocCell, 'Attributes', allocCell,    ...
      'Data', allocCell, 'Children', allocCell);

    for count = 1:numChildNodes
        theChild = childNodes.item(count-1);
        children(count) = makeStructFromNode(theChild);
    end
end

% ----- Local function MAKESTRUCTFROMNODE -----
function nodeStruct = makeStructFromNode(theNode)
% Create structure of node info.

nodeStruct = struct(                        ...
   'Name', char(theNode.getNodeName),       ...
   'Attributes', parseAttributes(theNode),  ...
   'Data', '',                              ...
   'Children', parseChildNodes(theNode));

if any(strcmp(methods(theNode), 'getData'))
   nodeStruct.Data = char(theNode.getData); 
else
   nodeStruct.Data = '';
end

% ----- Local function PARSEATTRIBUTES -----
function attributes = parseAttributes(theNode)
% Create attributes structure.

attributes = [];
if theNode.hasAttributes
   theAttributes = theNode.getAttributes;
   numAttributes = theAttributes.getLength;
   allocCell = cell(1, numAttributes);
   attributes = struct('Name', allocCell, 'Value', ...
                       allocCell);

   for count = 1:numAttributes
      attrib = theAttributes.item(count-1);
      attributes(count).Name = char(attrib.getName);
      attributes(count).Value = char(attrib.getValue);
   end
end

它易于使用，

str = 'http://stackoverflow.com/feeds/question/25047975';
x = parseXML(str);

要查找所有<cs>个节点，您可以执行树遍历，并选择名称为name的所有节点的属性unit和cs。

阅读XML文件Matlab

1 个答案: