我在CompanyApplication类中有以下三种方法(以及列出的支持工厂和服务):
public ResultSet<CompanyDto> AddCompany(CompanyDto companyDto)
{
var result = new CompanyDto();
var company = new Company();
Mapper.Map(companyDto, company);
using (ITransaction t = _transactionFactory.Create())
{
company = _companyService.Add(company);
t.Commit();
}
Mapper.Map(company, result);
return new ResultSet<CompanyDto>(1, new[] { result });
}
public ResultSet<CompanyContactDto> AddCompanyContact(CompanyContactDto companyContactDto)
{
var result = new CompanyContactDto();
var company = new Company();
var contact = new CompanyContact();
Mapper.Map(companyContactDto, contact);
using (ITransaction t = _transactionFactory.Create())
{
var contactCompanies = FindByIdJoin<Company, CompanyDto>(companyContactDto.CompanySK);
Mapper.Map(contactCompanies.Data.First(), company);
company.CompanyContacts.Add(contact);
company = _companyService.Update(company);
t.Commit();
}
Mapper.Map(contact, result);
return new ResultSet<CompanyContactDto>(1, new[] { result });
}
public ResultSet<T_DtoType> FindByIdJoin<T_DbType, T_DtoType>(long id)
{
IAbstractRepository<T_DbType> repository = EnsureRepository<T_DbType>();
T_DbType entity = repository.FindByIdJoin(id);
return (entity == null ? null : MapResultSetToDto<T_DbType, T_DtoType>(entity));
}
此处还有其他对象,这就是为什么FindByIdJoin
已成为CompanyApplication类中的单独方法。
我已经使用一些模拟和CompanyApplication类的实例设置了测试类:
private Mock<ICompanyRepository> _mockCompanyRepository;
private Mock<ICompanyDomain> _mockCompanyService;
private Mock<ITransactionFactory> _mockTransactionFactory;
private Mock<ITransaction> _mockTransaction;
private CompanyApplication _companyApplication;
[Setup]
public void SetUp()
{
_mockCompanyRepository = new Mock<ICompanyRepository>(MockBehavior.Strict);
_mockCompanyService = new Mock<ICompanyDomain>(MockBehavior.Strict);
_mockTransactionFactory = new Mock<ITransactionFactory>(MockBehavior.Strict);
_mockTransaction = new Mock<ITransaction>(MockBehavior.Strict);
_companyApplication = new CompanyApplication(
_mockCompanyRepository.Object,
_mockCompanyService.Object,
_mockTransactionFactory.Object);
}
我已成功直接在Moq中测试FindByIdJoin
和AddCompany
方法,如下所示:
[Test]
public void CanFindCompanyByIdJoin()
{
var data = new Company {ObjectId = 1, Name = "Company1"};
_mockCompanyRepository.Setup(x => x.FindByIdJoin(It.Is<long>(arg => arg == data.ObjectId)))
.Returns(data);
var result = _companyApplication.FindByIdJoin<Company, CompanyDto>(data.ObjectId);
Assert.AreEqual(data.ObjectId, result.Data.First().ObjectId);
}
[Test]
public void CanAddCompany()
{
var data = new Company {ObjectId = 1, Name = "Company1"};
_mockCompanyService.Setup(x => x.Add(It.Is<Company>(arg => arg.ObjectId == data.ObjectId)))
.Returns(data);
_mockTransactionFactory.Setup(x => x.Create()).Returns(_mockTransaction.Object);
_mockTransaction.Setup(x => x.Commit());
_mockTransaction.Setup(x => x.Dispose());
var dto = new CompanyDto {ObjectId = 1, Name = "Company1"};
var result = _companyApplication.AddCompany(dto);
_mockCompanyService.Verify(t => t.Add(It.IsAny<Company>()));
}
这两个测试通过就好了。但是,我在为AddCompanyContact
进行测试时遇到问题,因为它会将FindByIdJoin
作为其流程的一部分,而这似乎正在阻碍。
具体来说,有没有办法在var contactCompanies = FindByIdJoin<Company, CompanyDto>(companyContactDto.CompanySK)
方法的测试中模拟AddCompanyContact
?
谢谢!
答案 0 :(得分:0)
根据您想要做的工作量,我会看到两种选择。
以下示例:
public ResultSet<CompanyContactDto> AddCompanyContact(CompanyContactDto companyContactDto)
{
AddCompanyContact(CompanyContactDto, ()=>
{
return FindByIdJoin<Company, CompanyDto> companyContactDto.CompanySK);
}
}
public ResultSet<CompanyContactDto> AddCompanyContact(CompanyContactDto companyContactDto, Func<WhateverTheMethodReturns> findIdReplacement)
{
var result = new CompanyContactDto();
var company = new Company();
var contact = new CompanyContact();
Mapper.Map(companyContactDto, contact);
using (ITransaction t = _transactionFactory.Create())
{
var contactCompanies = findIdReplacement();
Mapper.Map(contactCompanies.Data.First(), company);
company.CompanyContacts.Add(contact);
company = _companyService.Update(company);
t.Commit();
}
Mapper.Map(contact, result);
return new ResultSet<CompanyContactDto>(1, new[] { result });
}
答案 1 :(得分:0)
我过度使问题变得复杂......因为AddCompanyContact
调用了FindByIdJoin
,所以我需要做的就是模仿FindByIdJoin
中使用的相同界面。
获得的经验:模拟接口,而不是类。