我正在开发一个使用android调用Web服务的项目。我使用ksoap2
。
我创建了一个自己的数据类型(只是为了尝试),它包含两个字符串变量。就像这样
public class MyType {
String fName;
String lName;
public MyType(String s1,String s2){
fName = s1;
lName = s2;
}
}
我在两端创建了这种数据类型。(Web服务端和android应用程序端)。我编写了一个程序来调用Web服务,然后使用我的数据类型连接给定的字符串。
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import java.io.IOException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParserException;
import android.os.AsyncTask;
import android.widget.TextView;
public class MainActivity extends ActionBarActivity {
public final static String URL = "http://192.168.69.1:8080/WebApplication4/MyWebService?wsdl";
public static final String NAMESPACE = "http://mywebservice.android.com/";
public static final String SOAP_ACTION_PREFIX = "/";
private static final String METHOD = "objectMethod";
private TextView textView;
MyType mt = new MyType("Upul","Tharanga");
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
textView = (TextView) findViewById(R.id.test);
AsyncTaskRunner runner = new AsyncTaskRunner(mt);
runner.execute();
}
private class AsyncTaskRunner extends AsyncTask<Integer, String, String> {
private String resp;
MyType a;
public AsyncTaskRunner(MyType a){
this.a = a;
}
@Override
protected String doInBackground(Integer... params) {
publishProgress("Loading contents..."); // Calls onProgressUpdate()
try {
// SoapEnvelop.VER11 is SOAP Version 1.1 constant
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
SoapObject request = new SoapObject(NAMESPACE, METHOD);
PropertyInfo pi1=new PropertyInfo();
pi1.setType(String.class);
pi1.setName("parameter");
pi1.setValue(a);
request.addProperty(pi1);
envelope.bodyOut = request;
HttpTransportSE transport = new HttpTransportSE(URL);
try {
transport.call(NAMESPACE + SOAP_ACTION_PREFIX + METHOD, envelope);
} catch (IOException e) {
e.printStackTrace();
} catch (XmlPullParserException e) {
e.printStackTrace();
}
//bodyIn is the body object received with this envelope
if (envelope.bodyIn != null) {
//getProperty() Returns a specific property at a certain index.
//SoapPrimitive resultSOAP = (SoapPrimitive) ((SoapObject) envelope.bodyIn).getProperty(0);
//Object resultSOAP = (SoapPrimitive)((SoapObject) envelope.bodyIn).getProperty(0);
Object resultSOAP = (SoapPrimitive)((SoapObject) envelope.bodyIn).getProperty(0);
resp=resultSOAP.toString();
}
} catch (Exception e) {
e.printStackTrace();
resp = e.getMessage();
}
return resp;
}
/**
*
* @see android.os.AsyncTask#onPostExecute(java.lang.Object)
*/
@Override
protected void onPostExecute(String result) {
// execution of result of Long time consuming operation
// In this example it is the return value from the web service
textView.setText(result);
}
/**
*
* @see android.os.AsyncTask#onPreExecute()
*/
@Override
protected void onPreExecute() {
// Things to be done before execution of long running operation. For
// example showing ProgessDialog
}
/**
*
* @see android.os.AsyncTask#onProgressUpdate(Progress[])
*/
@Override
protected void onProgressUpdate(String... text) {
textView.setText(text[0]);
// Things to be done while execution of long running operation is in
// progress. For example updating ProgessDialog
}
}
}
我的Web服务所做的是将MyType参数作为输入并连接这两个给定的字符串并返回连接的字符串。 当我运行Android应用程序时,我收到一个错误(我认为是运行时错误),说无法序列化MyType。 有什么建议可以解决这个问题?
答案 0 :(得分:1)
尝试实施可序列化
public class MyType implements Serializable {
String fName;
String lName;
public MyType(String s1,String s2){
fName = s1;
lName = s2;
}
}