我正在使用一个库,该库除了其他参数之外还包含一个名称数组,并创建一个<select>
组合框,其中包含以该数组中的名称命名的<option>
元素。它还为value
节点的<option>
属性分配了获取名称的索引的值。因此,例如,如果数组的索引0包含“foo”,那么它将创建如下标记:<option value="0">foo</option>
。作为参考,这是该库的代码:
function generateSelect(objDimensionAssoc, obj, select_name, label_name, function_name, state, DivAlignement)
{
//Valid object before
sChaine = "";
if( (obj != null) && (obj != undefined) && (obj != "") && (parseInt(countObject(obj)) > 0) ){
if( state == 'show' ){
sChaine +="<label for='"+select_name+"' ><span>"+label_name+"</span></label>\n";
sChaine +="<div class='"+DivAlignement+"'>\n";
if(function_name != "")
sChaine +="<select name='"+select_name+"' id='"+select_name+"' onchange='"+function_name+"' >\n";
else
sChaine +="<select name='"+select_name+"' id='"+select_name+"'>\n";
//lang = variable reconnu dans tout les pages
for (var x=0; x < obj.length; x++){
//One or two domentionnal array
if(obj[x] != null){
if(objDimensionAssoc == "1"){
if(chaineUrl){
sChaine += compare_and_create( x, obj[x], chaineUrl[select_name], select_name);
} else {
sChaine += compare_and_create( x, obj[x], "", select_name);
}
} else {
if(chaineUrl){
sChaine += compare_and_create( x, obj[x][lang], chaineUrl[select_name], select_name);
} else {
sChaine += compare_and_create( x, obj[x][lang], "", select_name);
}
}
}
}
sChaine +="</select>\n";
sChaine +="</div>\n";
}
return(sChaine);
} else {
//empty array
if( state == 'show' ){
sChaine +="<label for='"+select_name+"' ><span>"+label_name+"</span></label>\n";
sChaine +="<div class='"+DivAlignement+"'>\n";
sChaine +="<select name='"+select_name+"' id='"+select_name+"' disabled='true' >\n";
sChaine +="<option value='0'> </option>\n";
sChaine +="</select>\n";
sChaine +="</div>\n";
}
return(sChaine);
}
}
function compare_and_create( key, innerText, string_compare,select_name)
{
if(key == string_compare){
return ("<option value='"+key+"' selected='selected'>"+innerText+"</option>\n");
} else {
return ("<option value='"+key+"'>"+innerText+"</option>\n");
}
}
这就是我所说的:
myDiv = document.getElementById('tmp_stationDiv');
var stationsList = new Array();
stationsList = JSON.parse(<?php getStationList($regions); ?>);
myDiv.innerHTML = generateSelect("1",stationsList,
"slt_idStations",message["txt_choose_station"][lang],
'','show','blockDiv');
这是函数getStationList()
:
function getStationList($regions)
{
$slt_nomStations = (isset($_GET["slt_nomStations"]) ? $_GET["slt_nomStations"] : 0);;
$db = ConnectionFactory::getFactory()->getConnection();
$stmt = $db->prepare("SELECT DISTINCT S.station_id, S.name, SA.sub_area_name FROM dev.Station AS S INNER JOIN dbo.SubArea AS SA ON S.sub_area_id = SA.sub_area_id INNER JOIN data.MonthlyNormalData as MND ON MND.station_id = S.station_id WHERE sub_area_name = '$regions[$slt_nomStations]' AND value IS NOT NULL ORDER BY S.name ASC");
$stmt->execute();
$stations = array();
$lastStationName = "";
while ($row = $stmt->fetch())
{
if ($lastStationName != $row['name'])
{
array_push($stations, $row['name']);
$lastStationName = $row['name'];
}
}
$newJSArray = json_encode($stations);
echo json_encode($newJSArray);
}
现在这完全没问题。 getStationList()
的输出例如是"[\"LA GRANDE RIVIERE A\"]"
,然后我使用JSON.parse()
将其转换为javascript数组。
不幸的是,与value
节点关联的<option>
将为0,1,2,...,n,其中n是站点数量 - 1.我想关联具有站ID的站的名称(我从数据库中恢复),因此与value
节点关联的<option>
将是那些ID。为此,我想我需要在相应ID的索引处推送站的名称。我尝试对getStationList()
进行以下修改:
function getStationList($regions)
{
$slt_nomStations = (isset($_GET["slt_nomStations"]) ? $_GET["slt_nomStations"] : 0);;
$db = ConnectionFactory::getFactory()->getConnection();
$stmt = $db->prepare("SELECT DISTINCT S.station_id, S.name, SA.sub_area_name FROM dev.Station AS S INNER JOIN dbo.SubArea AS SA ON S.sub_area_id = SA.sub_area_id INNER JOIN data.MonthlyNormalData as MND ON MND.station_id = S.station_id WHERE sub_area_name = '$regions[$slt_nomStations]' AND value IS NOT NULL ORDER BY S.name ASC");
$stmt->execute();
$IDs = array();
$names = array();
$stations = array();
$lastStationName = "";
while ($row = $stmt->fetch())
{
if ($lastStationName != $row['name'])
{
array_push($names, $row['name']);
array_push($IDs, $row['station_id']);
$lastStationName = $row['name'];
}
}
$stations = array_fill_keys($IDs, $names);
$newJSArray = json_encode($stations);
echo json_encode($newJSArray);
}
不幸的是,这不起作用,因为getStationList()
函数的输出现在是这样的:"{\"6047\":[\"LA GRANDE RIVIERE A\"]}"
。那么我将如何修改我的代码以生成我的<select>
节点及其子<option>
节点,其value
属性设置为每个相应电台名称的ID?< / p>
答案 0 :(得分:1)
为什么不喜欢
$arr = array()
while ($row = $stmt->fetch()) {
$arr[$row['stationID']] = $row['stationName'];
}
您正在使用array_push,它不允许您为推送值指定密钥 - 您只需获得下一个更高的可用索引。所以不要使用数组_ *()函数,只需直接填入键/值对。