Question

在一个页面中，它应显示下拉菜单中包含以下所选月份的记录，并在？month = March

中设置

因此查询将执行此操作

$sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC";

但它显示完成列中值为2的记录，我不希望查询包含此内容。

我试过

$sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC";

但它显示了不同月份的记录。

所以基本上我希望记录排除记录中 2 的记录，这些记录将不会显示在页面中。

Answer 1

您的第一个查询应该执行您想要的操作。不应返回finished = '2'行。

忽略您的第二个查询中可能应该修复的错误：

$sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) .
       "' AND (finished='0' OR finished = '1' OR finished = '3') ORDER BY date ASC";

区别在于OR子句的括号，因为AND的绑定比OR更强。

您还可以使用IN更简洁地获得相同的结果：

$sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) .
       "' AND finished IN ('0', '1', '3') ORDER BY date ASC";

Answer 2

AND finished='0' OR finished = '1' OR finished = '3'

到

AND finished != 2

或

AND (finished = 0 OR finished = 1 OR finished = 3)

MySQL查询异常

2 个答案: