PHP SQL返回计数最高的字段

Question

我需要一个返回包含最高计数的网站的查询。

请参阅下面的示例表：

字段：

id | site

1  | site1
2  | site2
3  | site3
4  | site3 

在上面这种情况下，它应该返回site3。

我该怎么做？

Answer 1

select site, count(id) from table group by site order by count(id) desc limit 1

应该工作

Answer 2

SQL Server（SQL Fiddle）：

SELECT TOP 1 site
FROM MyTable
GROUP BY site
ORDER BY COUNT(*) DESC

或MySQL（SQL Fiddle）：

SELECT site 
FROM MyTable
GROUP BY site
ORDER BY COUNT(*) DESC
LIMIT 1

Answer 3

试试这个：

SELECT site, 
         COUNT(site) TotalCount
    FROM table_name
GROUP BY site
  ORDER BY count(id) DESC LIMIT 1

Answer 4

如果你想要字段网站，那么这里是查询：

SELECT COUNT(site), site FROM tab GROUP BY site DESC LIMIT 1

Answer 5

这个应该有效

select max(C), S from (select count(id) C ,site S from table group by site) tab

Answer 6

简单count和group您的查询和order by计数列

SELECT 
      COUNT(id) as amount, 
      site 
FROM sitetable 

GROUP BY site 
ORDER BY amount DESC 
LIMIT 1

Answer 7

SELECT MAX（id）AS id，site FROM demo

它的归来 id site
4 site3