Question

var spclChrs="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789-_";

/*Accepted Characters*/
var id = $(this).attr('id');
var textVal = $("#" + id).val();
$("#" + id).css({ "background": "", "border": "" });
for (var i = 0; i < textVal.length; i++) {
    if (spclChrs.indexOf(textVal.charAt(i)) == -1) {
        if (sessionLang == 0) {
            $().toastmessage('showErrorToast', "Invalid  character(s) entered.");
        }
        if (sessionLang == 1) {
            $().toastmessage('showErrorToast', "Los caractere(s) entraron.");
        }
        $("#" + id).css({ "background": "#FFCECE", "border": "1px solid red", });
        textVal = textVal.slice(0, -1);
        $("#" + id).val(textVal);
        return false;
    }
}

我对keyup和keydown事件的文本框进行了以下验证。我接受我的变量＆＃34; spclChars＆＃34;中指定的字符。而不是手动指定字符，我如何通过Ragex保持我的代码相同。

Answer 1

我想说以下是你的目标：

// Regular expression to check against
// [^ creates a negative character class, saying that it only looks for characters NOT defined in this class
// \w = Any (english) alphanumerical characters (a-zA-Z0-9)
// -_
// ] end of class
// This [^\w-_] means any character that isn't a-zA-Z0-9-_.
// g = global flag
var reg = /[^\w-_]/g;   

var id = $(this).attr('id');
var textVal = $("#" + id).val();
$("#" + id).css({ "background": "", "border": "" });

// Test the string towards the regular expression
// true = fits the expression (Have used special characters)
// false = Doesn't fit (only used a-zA-Z0-9-_)
if (reg.test(textVal)) {
    if (sessionLang == 0) {
        $().toastmessage('showErrorToast', "Invalid  character(s) entered.");
    }

    if (sessionLang == 1) {
        $().toastmessage('showErrorToast', "Los caractere(s) entraron.");
    }
    $("#" + id).css({ "background": "#FFCECE", "border": "1px solid red", });
    textVal = textVal.slice(0, -1);
    $("#" + id).val(textVal);
    return false;

PS：你的例子最后似乎缺少一些代码：）

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