我想裁剪一个矩形大小的UIImageView它应该是可调整大小的,请任何人帮助我,我正在努力。
答案 0 :(得分:0)
您可以使用以下代码添加平移手势,您可以从中移动图像视图和捏合手势,通过该手势可以调整图像大小
-(void)addGesture {
UIPanGestureRecognizer *panRecognizer = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(move:)];
[panRecognizer setMinimumNumberOfTouches:1];
[panRecognizer setMaximumNumberOfTouches:1];
[imgView addGestureRecognizer:panRecognizer];
UIPinchGestureRecognizer *pinchRecognizer = [[UIPinchGestureRecognizer alloc] initWithTarget:self action:@selector(resize:)];
[imgView addGestureRecognizer:pinchRecognizer];
}
-(void)move:(id)sender {
[self.view bringSubviewToFront:[(UIPanGestureRecognizer*)sender view]];
CGPoint translatedPoint = [(UIPanGestureRecognizer*)sender translationInView:self.view];
if ([(UIPanGestureRecognizer*)sender state] == UIGestureRecognizerStateBegan) {
firstX = [[sender view] center].x;
firstY = [[sender view] center].y;
}
translatedPoint = CGPointMake(firstX+translatedPoint.x, firstY);
[[sender view] setCenter:translatedPoint];
}
- (void)resize:(UIPinchGestureRecognizer *)recognizer
{
if([recognizer state] == UIGestureRecognizerStateBegan) {
_lastScale = 1.0;
if ([recognizer numberOfTouches] >= 2) { //should always be true when using a PinchGR
CGPoint touch1 = [recognizer locationOfTouch:0 inView:self.imageForEditing];
CGPoint touch2 = [recognizer locationOfTouch:1 inView:self.imageForEditing];
CGPoint mid;
mid.x = ((touch2.x - touch1.x) / 2) + touch1.x;
mid.y = ((touch2.y - touch1.y) / 2) + touch1.y;
CGSize imageViewSize = self.imageForEditing.frame.size;
CGPoint anchor;
anchor.x = mid.x / imageViewSize.width;
anchor.y = mid.y / imageViewSize.height;
self.imageForEditing.layer.anchorPoint = anchor;
}
}
CGFloat scale = 1.0 - (_lastScale - [recognizer scale]);
CGAffineTransform currentTransform = self.imageForEditing.transform;
CGAffineTransform newTransform = CGAffineTransformScale(currentTransform, scale, scale);
[self.imageForEditing setTransform:newTransform];
_lastScale = [recognizer scale];
}